الفيزياء العامة الجزء الثاني#موقع الفيزياء.كوم

Direct Current Circuits
ξ 1
ξ 2
a
b
a
b
R 1 I R 1 3
I 3 I 2
c
R 2
d
Figure 8.12
For loop a on the left side starting at point b we get
+ξ 1 - I 1 R 1 + I 3 R 3 = 0 (2)
For loop b on the left side starting at point b we get
- I 3 R 3 - I 2 R 2 - ξ 2 = 0 (3)
Equations (1), (2), and (3) can be solved to find the unknowns currents I 1 , I 2 ,
and I 3 .
The current can be either positive or negative, depending on the
relative sizes of the emf and of the resistances.
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