الفيزياء العامة الجزء الثاني#موقع الفيزياء.كوم

Direct Current Circuits
In figure (c), the current 1.93A goes through the 2.94Ω equivalent resistor
to give a voltage drop of:
V = IR = (1.93)(2.94) = 5.68V
From figure (b), we see that this voltage drop is the same across V ab , the
10Ω resistor, and the 5Ω resistor.
Therfore
V ab = 5.68V
Since the current through the 20Ω resistor is also the current through the
25Ω
I = V ab /R ab = 5.68/25 = 0.227A
Example 8.10
Determine the current in each of the branches of the circuit shown in figure
8.17.
3Ω
8Ω
5Ω
1Ω
4V
1Ω
12V
Figure 8.17
Solution
First we should define an arbitrary direction for the
current as shown in the figure below.
I 1 I 2 I 3
I 3 = I 1 + I 2 (1)
By the voltage rule the left-hand loop
+I 1 (8Ω)-I 2 (5Ω)-I 2 (1Ω)-4V=0 (2)
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