الفيزياء العامة الجزء الثاني#موقع الفيزياء.كوم

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Direct Current CircuitsIn figure (c), the current 1.93A goes through the 2.94Ω equivalent resistorto give a voltage drop of:V = IR = (1.93)(2.94) = 5.68VFrom figure (b), we see that this voltage drop is the same across V ab , the10Ω resistor, and the 5Ω resistor.TherforeV ab = 5.68VSince the current through the 20Ω resistor is also the current through the25ΩI = V ab /R ab = 5.68/25 = 0.227AExample 8.10Determine the current in each of the branches of the circuit shown in figure8.17.3Ω8Ω5Ω1Ω4V1Ω12VFigure 8.17SolutionFirst we should define an arbitrary direction for thecurrent as shown in the figure below.I 1 I 2 I 3I 3 = I 1 + I 2 (1)By the voltage rule the left-hand loop+I 1 (8Ω)-I 2 (5Ω)-I 2 (1Ω)-4V=0 (2)www.hazemsakeek.com
Lectures in General PhysicsFor the right-hand loop4V+I 2 (5Ω+1Ω)+I 3 (4Ω)-12V=0 (3)Substitute for I 3 from eqn. (1) into eqns. (2)&(3)8I 1 -6I 2 -4=0 (4)4+6I 2 +4(I 1 +I 2 )-12=0 (5)Solving eqn. (4) for I 2I28 1− 4= I6Rearranging eqn. (5) we getI10+ I41 2=84Substitute for I 2 we getThen,I 1 +3.33I 1 -1.67=2I 1 =0.846AI 2 =0.462AI 3 =1.31ADr. Hazem Falah Sakeek
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LECTURES INGENERAL PHYSICSPart TwoE
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محاضرات في الفيزيا
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ContentsChapter (1) Electrostatic1.
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4.5 Energy stored in a charged capa
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Introduction to ElectrostaticsPart
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Introduction to ElectrostaticsIntro
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Introduction to ElectrostaticsWe ha
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Introduction to Electrostaticssame
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Introduction to Electrostatics1.2 P
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Introduction to ElectrostaticsRubbe
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Coulomb’s Lawقانون آولو
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Coulomb’s LawCoulomb’s lawقا
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Coulomb’s Law2.2 Calculation of t
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Coulomb’s Lawq 1 &q 3نتيجة
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Coulomb’s Lawx∑∑FFxy= 2 × 0.
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Coulomb’s LawExample 2.4A charge
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Coulomb’s LawExample 2.5Two fixed
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Coulomb’s Law2.3 Problems2.1) Two
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Lectures in General Physicsالكه
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Lectures in General PhysicsElectric
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3.3 The direction of E rLectures in
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Lectures in General PhysicsExample
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Lectures in General PhysicsE y = E
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Notice that the rule of drawing the
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Lectures in General Physics3.8 Solu
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Lectures in General PhysicsE y = -E
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Lectures in General Physics3.10 Pro
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Lectures in General Physics3.16) Ch
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Electric FluxElectric Flux4.1 The E
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Electric Flux4.1 The Electric Flux
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Electric Fluxوالمقصود ب ne
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Electric FluxExample 4.2In figure 4
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Electric Flux1 q∴ E =(4.6)24πε
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Electric Flux4.7 Applications of Ga
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Electric FluxA linear charge distri
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Electric FluxAn insulated conductor
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Electric FluxFor r<aAaRrFigure 4.17
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Electric Flux4.8 Solution of some s
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المجالElectric Fluxلاحظ
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Electric FluxExample 4.7Consder a l
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Electric Flux4.9 Problems4.1) An el
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Electric FluxGauss’s law to find
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Lectures in General PhysicsElectric
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Lectures in General Physicsمثال
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Lectures in General Physics5.1 Defi
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Lectures in General Physics5.3 Elec
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Lectures in General Physics5.4 Pote
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Lectures in General Physics5.6 The
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Lectures in General PhysicsSolution
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Lectures in General Physics5.9 Solu
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Lectures in General Physics5.9) Con
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Multiple Choice QuestionsPart 1Prin
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Lectures in General Physicsmkmmkmab
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Lectures in General Physicsy3 nC0.2
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Lectures in General Physicsdensity
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Lectures in General Physics[24] A s
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Lectures in General PhysicsEEFigure
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Lectures in General PhysicsQ. No. A
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Lectures in General Physicsالمك
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Lectures in General PhysicsCapacito
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Lectures in General Physics6.3 Calc
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6.3.2 Cylindrical capacitorLectures
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6.4.2 Capacitors in series:Lectures
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Lectures in General PhysicsAm4 4AgA
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Lectures in General PhysicsTherefor
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Lectures in General Physics2QW = U
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Lectures in General Physics(b) We f
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CQο οο= = = κ(6.20)VdVQοκQVο
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Lectures in General Physics2qF =2ε
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Lectures in General Physics6.23) A
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LengthMetric and Imperial Measures1
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Lectures in General PhysicsPeriodic
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Lectures in General PhysicsAPPENDIX
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Lectures in General PhysicsOpticsOp
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Lectures in General PhysicsAmerican
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APPENDIX (E)BibliographyLectures in
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APPENDIX (F)IndexLectures in Genera
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الفيزياء العامة الجزء الثاني#موقع الفيزياء.كوم

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