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Physics for Geologists, Second edition

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water above a vertical thickness h of water-saturated sand:<br />

Fluids and fluid flow 1 19<br />

The depth of water does, of course, contribute to the total stress, S.<br />

Reynolds numbers<br />

Osborne Reynolds (1842-1912) carried out some beautiful experiments in<br />

the 1880s on the flow of water in pipes, and was interested in the conditions<br />

that separated the stable from the unstable, the laminar from the turbulent.<br />

He found that it was a function of the internal diameter of the pipe and the<br />

velocity and viscosity of the water in it, but argued that since units are arbi-<br />

trary, there must be a dimensionless relationship. Noting that the dimensions<br />

of kinematic viscosity (v = qlp) are those of a length multiplied by a veloc-<br />

ity, he took as his dimensionless number dV/v, where d is the diameter of<br />

the pipe and V is the velocity of the liquid (volume per unit area normal to<br />

flow, L~T-' LP2 = LT-l). This is now called a Reynolds number. It con-<br />

sists of a characteristic length multiplied by a characteristic velocity divided<br />

by the kinematic viscosity of the fluid. It has the indefinite article because<br />

there are different ways of defining the components. (Reynolds actually took<br />

the inverse of this but it was changed to the <strong>for</strong>m given, presumably to give<br />

a large number rather than a small fraction, and that is how it is now defined.)<br />

In pipe and channel flow, the characteristic length is the hydraulic radius<br />

(which we shall come to shortly). What should it be in porous rocks? It is<br />

common practice to take the mean grain size, but this is a very indirect quan-<br />

tity because it is precisely the part of the rock that fluids do not flow through.<br />

We shall return to this problem when we consider water flow through porous<br />

rocks.<br />

Hydraulic radius<br />

With pipe flow, there is no difficulty in measuring the radius. But what if the<br />

pipe were square or elliptical? or if the pipe were not quite full?<br />

It has been found that the unifying parameter is obtained by taking the<br />

volume of water and dividing it by its wetted surface (if the dimensions<br />

remain constant, you can take the cross-sectional area divided by the wetted<br />

perimeter). This is called the hydraulic radius, and it has the dimension of<br />

length. The hydraulic radius of a pipe of circular cross-section and constant<br />

internal diameter d is<br />

If we never used anything but pipes that were full, this would not be neces-<br />

sary. But pipes are not always full, and water can flow in channels as well<br />

as pipes.<br />

Copyright 2002 by Richard E. Chapman

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