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Physics for Geologists, Second edition

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22 Force<br />

How does momentum differ from kinetic energy? Momentum has the<br />

dimensions of mass x velocity [MLT-'1 while kinetic energy has the dimensions<br />

of mass x velocity squared [ML~T-~]. Both are conserved, and both<br />

can be transferred to other bodies, but kinetic energy can be converted to<br />

other <strong>for</strong>ms of energy, as we have seen. Momentum is a property of a moving<br />

mass that can be imparted to other bodies on impact.<br />

Earlier we asked why pieces of artificial satellites return to Earth from time<br />

to time when Equation 2.5 seems to suggest that as a satellite slows down<br />

its height h above the Earth will increase.<br />

It is a matter of energy. The satellite has energy due to its motion in orbit<br />

and due to its position in the gravitational field of the Earth. Its kinetic<br />

energy is<br />

where o is the angular velocity (in rads-l: the right hand side uses<br />

Equation 2.5). The potential energy is found by considering the work<br />

required to move the mass m in the gravitational field from a distance x<br />

from the earth's centre of gravity to x + 6x. This, from Equation 2.2, is<br />

The work done in moving the mass m from x to oo, where the potential<br />

energy is zero, is<br />

Hence the potential energy at (RE + h) is<br />

and the total energy is the sum of the kinetic and potential energies,<br />

This is negative, so as the kinetic energy decreases and the total energy<br />

becomes a larger negative number, h also decreases; and as h decreases,<br />

its speed increases until it enters the atmosphere, where frictional resistance<br />

slows it down and it returns to Earth. Why is the potential energy nega-<br />

tive, and what meaning is to be attached to negative potential energy? If<br />

a satellite is considered to have zero potential energy when effectively iso-<br />

lated from the gravitational field of its planet, and you have to do work on it<br />

to get it there from its orbit, then its potential energy in its orbit is negative<br />

(Ep + work = 0).<br />

Let us now gather all those quantities together in one table (Table 2.1).<br />

Copyright 2002 by Richard E. Chapman

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