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Physics for Geologists, Second edition

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16 Force<br />

Figure 2.1 The sum of the <strong>for</strong>ces acting on a static body must be zero. The<br />

normal reaction is equal to the component of weight normal to the<br />

surface; and the frictional resistance is equal to the component of<br />

weight down the surface.<br />

Normal<br />

reaction<br />

Figure 2.2 A triangle of <strong>for</strong>ces.<br />

of these must be zero. As long as the frictional resistance can equal the<br />

component of weight down the slope, the book will remain stationary.<br />

When the sum of <strong>for</strong>ces equals zero, the relationship can be expressed in<br />

another way called Lami's Theorem, or the triangle or polygon of <strong>for</strong>ces.<br />

If three <strong>for</strong>ces in the same plane act at a point in a stationary object (such<br />

as the centre of mass), then three lines drawn parallel to these <strong>for</strong>ces with<br />

lengths proportional to the magnitude of each <strong>for</strong>ce <strong>for</strong>m the three sides of<br />

a triangle. So the book on an inclined surface (Figure 2.1) is acted on by the<br />

weight of the book, the normal reaction, and the frictional resistance, and<br />

this can be represented by a triangle of <strong>for</strong>ces, as in Figure 2.2.<br />

When it slides, there is no longer a triangle of <strong>for</strong>ces because the shear<br />

component of weight, T, is greater than the frictional resistance, t.<br />

If more than three <strong>for</strong>ces act on a body at rest, a polygon of <strong>for</strong>ces results.<br />

Coriolis <strong>for</strong>ce<br />

Why does the carousel attendant at the fun fair have to lean over in order<br />

to walk radially outwards from the centre? Why do the ocean currents in<br />

the same hemisphere circulate the same way, but those in opposite hemi-<br />

spheres the opposite way? Why does a cyclone or typhoon in the Southern<br />

Hemisphere rotate clockwise when viewed from above, but anti-clockwise<br />

in the Northern Hemisphere?<br />

Copyright 2002 by Richard E. Chapman

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