Physics for Geologists, Second edition
Physics for Geologists, Second edition
Physics for Geologists, Second edition
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120 Fluids and fluid flow<br />
The hydraulic radius is perhaps best understood with channel flow. Con-<br />
sider unit length of water in laminar flow down a gently inclined channel of<br />
width w, the depth of the water normal to the bottom being h. Its volume<br />
is wh, and its wetted surface is w + 2h. The <strong>for</strong>ces acting on this volume<br />
of water are gravitational (the component of weight down the slope 8) and<br />
frictional (the resistance of the wetted surface mainly but also the viscosity<br />
of the water). With laminar flow, these are equal and opposite, so<br />
whpg sin 8 - tO(w + 2h) = O), (12.5)<br />
where t o is the boundary shear stress. So the ratio of boundary shear stress<br />
to the component of weight of unit volume down the slope is<br />
-- to - wh<br />
pg sin 0 (w + 2h) '<br />
This is the volume divided by the wetted surface area - the hydraulic radius.<br />
The hydraulic radius is a measure of both size and shape.<br />
It also applies to rivers, where it is called the hydraulic depth because<br />
the right-hand side of Equation 12.6 approaches h as w becomes large<br />
compared to h.<br />
Solids settling in static fluid<br />
If you place a small pebble at the surface of some static water and let it fall, it<br />
will accelerate until the frictional resistance of the water equals the weight of<br />
the pebble. Its velocity will then be constant at what is known as its terminal<br />
velocity. Likewise, if you jump out of an aeroplane without a parachute, the<br />
speed at which you hit the ground will not be the same <strong>for</strong> all small heights,<br />
but once high enough to achieve your terminal velocity (about 200 km h-' if<br />
you spread your arms and legs, but nearer 240 km hkl if you go into a dive<br />
with your arms like swept-back wings), that will be the speed at which you<br />
hit the ground from any greater height (and it will be terminal!).<br />
The larger the solid object, the larger the sympathetic flow that will be<br />
generated by its passage through the water. The more solid objects there<br />
are, the larger will be the sympathetic flow. The shape also affects the speed<br />
at which the object falls. During the <strong>Second</strong> World War, a special bomb<br />
was designed to fall faster than the normal bomb so that it would penetrate<br />
deeper into the ground be<strong>for</strong>e exploding (it was called the earthquake bomb,<br />
and the idea was to shake down bridges and buildings: it worked). The other<br />
extreme is the parachute.<br />
Dimensional analysis can be used to find the <strong>for</strong>m of the equation giving<br />
the terminal velocity of a single small solid sphere:<br />
Copyright 2002 by Richard E. Chapman