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Mechanics of Fluids

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General energy equation for steady flow <strong>of</strong> any fluid 103<br />

With this particular distribution <strong>of</strong> velocity over the cross-section the term Further discussion <strong>of</strong><br />

u Example 3.1<br />

2 /2 is therefore about 6% too low to represent the mean kinetic energy<br />

divided by mass. It is usual, however, to disregard such discrepancy except<br />

where great accuracy is required. In any case, the exact value <strong>of</strong> the correction<br />

to be applied is much influenced by conditions upstream and is scarcely ever<br />

known. The correction should nevertheless be remembered if the Steady-<br />

Flow Energy Equation is applied to fully developed laminar flow in a circular<br />

pipe (see Chapter 6), for then the mean kinetic energy divided by mass =<br />

2u2 /2. Even so, as laminar flow is generally associated only with very low<br />

velocities the kinetic energy term would in these circumstances probably be<br />

negligible.<br />

3.5.4 The Steady-Flow Energy Equation in practice<br />

The Steady-Flow Energy Equation (SFEE) applies to liquids, gases and<br />

vapours, and accounts for viscous effects. In many applications it is considerably<br />

simplified because some <strong>of</strong> the terms are zero or cancel with others.<br />

If no heat energy is supplied to the fluid from outside the boundaries, and<br />

if the temperature <strong>of</strong> the fluid and that <strong>of</strong> its surroundings are practically<br />

identical (or if the boundaries are well insulated) q may be taken as zero.<br />

If there is no machine between sections (1) and (2) the shaft work divided<br />

by mass w is zero. And for fluids <strong>of</strong> constant density ϱ1 = ϱ2.<br />

If an incompressible fluid with zero viscosity flows in a stream-tube across<br />

which there is no transfer <strong>of</strong> heat or work, the temperature <strong>of</strong> the fluid<br />

remains constant. Therefore the internal energy is also constant and the<br />

equation reduces to<br />

0 =<br />

� p2<br />

ϱ2<br />

+ 1<br />

2 u2 � �<br />

p1<br />

2 + gz2 − +<br />

ϱ1<br />

1<br />

2 u2 �<br />

1 + gz1<br />

This is seen to be identical with Bernoulli’s equation (3.9).<br />

Real fluids have viscosity, and the work done in overcoming the viscous<br />

forces corresponds to the so-called fluid friction. The energy required to<br />

overcome the friction is transformed into thermal energy. The temperature<br />

<strong>of</strong> the fluid rises above the value for frictionless flow; the internal energy<br />

increases and, in general, the heat transferred from the fluid to its surroundings<br />

is increased. The increase <strong>of</strong> temperature, and consequently <strong>of</strong> internal<br />

energy, is generally <strong>of</strong> no worth (the temperature rise is normally only a very<br />

small fraction <strong>of</strong> a degree) and thus corresponds to a loss <strong>of</strong> useful energy.<br />

Moreover, as we have defined q as the heat transferred to the fluid divided<br />

by the mass <strong>of</strong> the fluid, a loss <strong>of</strong> heat from the system is represented by −q<br />

and so the total loss (divided by the mass <strong>of</strong> the fluid) is e2 − e1 − q. For<br />

a fluid <strong>of</strong> constant density it is usual to express this loss <strong>of</strong> useful energy,<br />

resulting from friction, as head loss due to friction, h f. Therefore<br />

h f = (e2 − e1 − q)/g

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