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Mechanics of Fluids

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452 Flow with a free surface<br />

liquid surface downstream is not maintained at too high a level, maximum<br />

discharge is achieved through the narrowest section, known as the throat,<br />

for the same reasons that the discharge over a broad-crested weir reaches a<br />

maximum in the absence <strong>of</strong> appreciable restrictions downstream. The flow<br />

at the throat is therefore critical, and the flume is said to be under free discharge<br />

conditions. For a rectangular section in which the streamlines are<br />

straight and parallel the velocity at the throat is therefore given by � (gh2),<br />

and the discharge by<br />

�<br />

Q = b2h2 (gh2) (10.32)<br />

where b2 represents the width <strong>of</strong> the throat, and h2 the corresponding depth.<br />

Measurements <strong>of</strong> b2 and h2 would therefore be sufficient for the calculation<br />

<strong>of</strong> the discharge. The exact position at which the critical conditions<br />

exist, however, is not easy to determine, and measurement <strong>of</strong> h2 is thus<br />

impracticable. If, however, there is negligible friction in the upstream, converging,<br />

part <strong>of</strong> the flume and the slope <strong>of</strong> the bed is also negligible over this<br />

distance, then<br />

h1 + u2 1<br />

2g = h2 + u2 2<br />

2g = h2 + h2 3<br />

=<br />

2 2 h2<br />

where suffix 1 refers to quantities upstream <strong>of</strong> the contraction.<br />

Moreover<br />

u1 = Q<br />

b1h1<br />

= b2h2<br />

�<br />

(gh2)<br />

b1h1<br />

and this expression substituted for u1 in eqn 10.33 gives<br />

h1 + 1<br />

� �2 b2 h3 2<br />

2g b1 h2 g =<br />

1<br />

3<br />

2 h2<br />

that is,<br />

(h1/h2) 3 + 1<br />

2 (b2/b1) 2 = 3<br />

2<br />

(h1/h2) 2<br />

(10.33)<br />

(10.34)<br />

Equation 10.34 shows that, since the ratio b2/b1 is fixed for a particular<br />

flume, the ratio <strong>of</strong> depths h1/h2 is constant whatever the rate <strong>of</strong> flow,<br />

provided that the discharge is free (i.e. the velocity at the throat is critical).<br />

Therefore eqn 10.32 may be rewritten<br />

Q = b2g 1/2 h 3/2<br />

2 = b2g1/2h 3/2<br />

1<br />

r 3/2<br />

(10.35)<br />

where r = h1/h2, and the rate <strong>of</strong> flow through a given flume may be<br />

determined by measuring the upstream depth h1.<br />

Since b1 > b2, the discharge divided by width q1 < q2, and thus, as<br />

Fig. 10.19 shows, h1 > h2 for tranquil flow upstream, that is, r > 1.<br />

The value <strong>of</strong> r is, <strong>of</strong> course, given by the solution <strong>of</strong> eqn 10.34. Of the<br />

three roots the only one meeting the requirement r > 1is<br />

r = 0.5 + cos(2θ/3)

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