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Mechanics of Fluids

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main. The depth <strong>of</strong> water in the tank is to be increased from<br />

0.1 m to 2.7 m in not more than 15 minutes. Assuming that f<br />

has the constant value 0.007, and neglecting energy losses other<br />

than pipe friction, determine the diameter <strong>of</strong> pipe required.<br />

7.26 A viscometer consists essentially <strong>of</strong> two reservoirs joined by a<br />

length <strong>of</strong> capillary tubing. The instrument is filled with liquid<br />

so that the free surfaces in the reservoirs are where the walls<br />

are in the form <strong>of</strong> vertical circular cylinders, each <strong>of</strong> diameter<br />

20 mm. The capillary tube is 1 mm diameter and 400 mm long.<br />

Initially the difference in the free surface levels is 40 mm, and,<br />

for a particular liquid <strong>of</strong> relative density 0.84, the time taken<br />

for the higher level to fall by 15 mm is 478 s. Neglecting end<br />

effects in the capillary tube and energy losses other than those<br />

due directly to viscosity, determine the viscosity <strong>of</strong> the liquid.<br />

7.27 Water flows at a steady mean velocity <strong>of</strong> 1.5 m · s −1 through a<br />

50 mm diameter pipe sloping upwards at 45 ◦ to the horizontal.<br />

At a section some distance downstream <strong>of</strong> the inlet the pressure<br />

is 700 kPa and at a section 30 m further along the pipe the<br />

pressure is 462 kPa. Determine the average shear stress at the<br />

wall <strong>of</strong> the pipe and at a radius <strong>of</strong> 10 mm.<br />

7.28 A fluid <strong>of</strong> constant density ϱ enters a horizontal pipe <strong>of</strong> radius<br />

R with uniform velocity V and pressure p1. At a downstream<br />

section the pressure is p2 and the velocity varies with radius<br />

r according to the equation u = 2V{1 − (r 2 /R 2 )}. Show that<br />

the friction force at the pipe walls from the inlet to the section<br />

considered is given by πR 2 (p1 − p2 − ϱV 2 /3).<br />

Problems 297

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