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Mechanics of Fluids

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62 Fluid statics<br />

<strong>of</strong> the free (i.e. atmospheric) surface divided by the first moment <strong>of</strong> the area<br />

about the intersection <strong>of</strong> its plane with that <strong>of</strong> the free surface.<br />

The centre <strong>of</strong> pressure is always lower than the centroid (except when the<br />

surface is horizontal) as the following calculation demonstrates.<br />

From the parallel axes theorem:<br />

so eqn 2.16 becomes<br />

(Ak 2 )Ox = (Ak 2 )C + Ay 2<br />

y ′ = (Ak2 )C + Ay 2<br />

Ay<br />

= y + (Ak 2 )C/Ay (2.17)<br />

Since a second moment <strong>of</strong> area is always positive it follows that y ′ > y. QED.<br />

We see also that the more deeply the surface is submerged, that is, the<br />

greater the value <strong>of</strong> y, the smaller is the contribution made by the last term<br />

in eqn 2.17 and the closer is the centre <strong>of</strong> pressure to the centroid. This<br />

is because, as the pressure becomes greater with increasing depth, its variation<br />

over a given area becomes proportionately smaller, so making the<br />

distribution <strong>of</strong> pressure more uniform. Thus where the variation <strong>of</strong> pressure<br />

is negligible the centre <strong>of</strong> pressure may be taken as approximately at the<br />

centroid. This is justifiable in gases, because in them the pressure changes<br />

very little with depth, and also in liquids provided the depth is very large<br />

and the area small.<br />

The expressions 2.16 and 2.17, it is re-emphasized, give the distance to<br />

the centre <strong>of</strong> pressure measured down the plane from the level <strong>of</strong> the free<br />

surface and not vertically.<br />

The x-coordinate <strong>of</strong> the centre <strong>of</strong> pressure may be determined by taking<br />

moments about Oy. Then the moment <strong>of</strong> δF is ϱgy sin θδAx and the total<br />

moment is<br />

Fx ′ �<br />

�<br />

= ϱgxy sin θdA = ϱg sin θ xydA<br />

so<br />

A<br />

x ′ =<br />

�<br />

A xydA<br />

Ay<br />

A<br />

(2.18)<br />

When the area has an axis <strong>of</strong> symmetry in the y direction, this axis may<br />

be taken as Oy and then �<br />

A xydA is zero, that is, the centre <strong>of</strong> pressure lies<br />

on the axis <strong>of</strong> symmetry. It will be noted from eqns 2.16 and 2.18 that the<br />

position <strong>of</strong> the centre <strong>of</strong> pressure is independent <strong>of</strong> the angle θ and <strong>of</strong> the<br />

density <strong>of</strong> the fluid. However, a constant value <strong>of</strong> ϱ was used; the relations<br />

are therefore valid only for a single homogeneous fluid.<br />

For the plane lamina <strong>of</strong> negligible thickness illustrated in Fig. 2.15, the<br />

force on one face would exactly balance the force on the other if both faces<br />

were in contact with the fluid. In most cases <strong>of</strong> practical interest, however,<br />

there is no continuous path in the fluid from one face <strong>of</strong> the plane to the<br />

other and therefore the pressures at corresponding points on the two faces<br />

are not necessarily the same. For example, the surface may be that <strong>of</strong> a plate<br />

covering a submerged opening in the wall <strong>of</strong> a reservoir, or a canal lock-gate

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