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Mechanics of Fluids

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312 Boundary layers, wakes and other shear layers<br />

is therefore difficult, and an experimental check on theoretical results is<br />

more easily obtained by measurements <strong>of</strong> the drag force exerted by the<br />

fluid on the plate. Table 8.1 shows, however, that results do not vary<br />

widely when different assumptions are used for the velocity distribution<br />

within the boundary layer. The usefulness <strong>of</strong> the approximate method is<br />

thus further demonstrated. Because <strong>of</strong> the asymptotic approach to the mainstream<br />

velocity, Blasius’s solution does not give a finite value <strong>of</strong> the boundary<br />

layer thickness, but the value <strong>of</strong> y at which the velocity is 0.99um is about<br />

4.91x/ √ (Rex), andu = 0.999um at y ≏ 6.01x/ √ (Rex).<br />

Example 8.4 Air <strong>of</strong> density 1.21 kg · m −3 and kinematic viscosity<br />

1.5 × 10 −5 m 2 · s −1 passes over a thin flat plate, <strong>of</strong> dimensions 1.2 m<br />

×1.2 m, parallel to the airstream. If transition takes place at the trailing<br />

edge <strong>of</strong> the plate, determine<br />

(a) the velocity <strong>of</strong> the airstream<br />

(b) the frictional drag <strong>of</strong> the plate, DF.<br />

Assume that transition takes place at Ret = 5 × 10 5 and the velocity<br />

pr<strong>of</strong>ile is given by<br />

u<br />

um<br />

= 3<br />

2<br />

�<br />

y<br />

�<br />

δ<br />

− 1<br />

2<br />

�<br />

y<br />

�3 δ<br />

Solution<br />

At the trailing edge x = xt = x l; Rex = Ret = Re l; θ = θ l.<br />

(a) Ret = umxt<br />

ν<br />

so<br />

um = νRet<br />

xt<br />

(b) From Table 8.1<br />

Hence<br />

= (1.5 × 10−5 ) m 2 · s −1 × (5 × 10 −5 )<br />

1.2 m<br />

θ = 0.646x<br />

√ Rex<br />

θ √ Rex<br />

x<br />

= 0.646 × 1.2 m<br />

�<br />

= cf Rex = 0.646<br />

� (5)(10 5 ) = 1.096 × 10 −3 m<br />

= 6.25 m · s −1

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