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Mechanics of Fluids

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460 Flow with a free surface<br />

✷<br />

result is complicated. The solution is therefore normally obtained by either<br />

a numerical or a graphical integration.<br />

The problem under investigation is more <strong>of</strong>ten that <strong>of</strong> determining the<br />

position in the channel at which a particular depth is reached, that is, l is<br />

required for a particular value <strong>of</strong> h, so eqn 10.42 may be inverted. Then<br />

l =<br />

� h2<br />

h1<br />

1 − u2 /gh<br />

dh (10.43)<br />

s − i<br />

The following example illustrates the general method <strong>of</strong> solution.<br />

Example 10.4 A dam is built across a channel <strong>of</strong> rectangular crosssection<br />

which carries water at the rate <strong>of</strong> 8.75 m 3 · s −1 . As a result the<br />

depth just upstream <strong>of</strong> the dam is increased to 2.5 m. The channel is<br />

5 m wide and the slope <strong>of</strong> the bed is 1 in 5000. The channel is lined<br />

with concrete (Manning’s n = 0.015). How far upstream is the depth<br />

within 100 mm <strong>of</strong> the normal depth?<br />

Solution<br />

To determine the normal depth h0 Manning’s formula is applied (with<br />

metre-second units):<br />

8.75 m3 · s−1 (5 × h0) m2 = u = m2/3i1/2 =<br />

n<br />

1<br />

� �2/3 � �1/2 5h0 1<br />

0.015 5 + 2h0 5000<br />

Solution by trial gives h0 = 1.800 m. Since the channel is rectangular<br />

in section the critical depth hc = � q2 /g �1/3 � �<br />

= 1.752 1/3<br />

/9.81 m =<br />

0.678 m. This value is considerably less than the actual depth and the<br />

flow is therefore tranquil.<br />

We require a solution <strong>of</strong> eqn 10.43 between the limits 2.5 m and<br />

(1.800+0.100) m = 1.9 m. To illustrate a simple technique <strong>of</strong> numerical<br />

integration it will be sufficient to divide the range <strong>of</strong> depth, 2.5–<br />

1.9 m, into three equal parts. Then, starting at the dam (the position<br />

where the depth is known) and proceeding upstream, the calculations<br />

may be set out in tabular form (Table 10.2; Fig. 10.41).<br />

This method is well suited to computer programming and it may be applied<br />

to channels <strong>of</strong> variable cross-section, roughness and slope by adopting suitable<br />

average values <strong>of</strong> these parameters over each increment <strong>of</strong> length �l.<br />

Moreover, although the given example concerns a backwater curve in tranquil<br />

flow, the same technique may be used for any type <strong>of</strong> gradually varied<br />

flow.<br />

For example, it may be used in calculating the position <strong>of</strong> a hydraulic<br />

jump. As we saw in Section 10.10 the depth h2 downstream <strong>of</strong> the jump is<br />

determined by the conditions there (e.g. the normal depth appropriate to the

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