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Mechanics of Fluids

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200 Laminar flow between solid boundaries<br />

Fig. 6.6<br />

magnitude τ on the lower face and τ + δτ, say, on the upper face in the<br />

directions shown in Fig. 6.6. (The indicated directions <strong>of</strong> the stresses follow<br />

the convention mentioned in Section 1.6.1 by which a stress in the x direction<br />

acts on the surface facing the direction <strong>of</strong> increase <strong>of</strong> y.) Let the piezometric<br />

pressure be p ∗ at the left-hand end face, and p ∗ + δp ∗ at the right-hand<br />

end face.<br />

Then, if the width <strong>of</strong> the element in the direction perpendicular to the page<br />

is δz, the total force acting on the element towards the right is<br />

{p ∗ − (p ∗ + δp ∗ )}δyδz +{(τ + δτ) − τ}δxδz<br />

But for steady, fully developed flow there is no acceleration and so this total<br />

force must be zero.<br />

∴ −δp ∗ δy + δτδx = 0<br />

Dividing by δxδy and proceeding to the limit δy → 0, we get<br />

δp ∗<br />

δx<br />

= ∂τ<br />

∂y<br />

(6.16)<br />

For laminar flow <strong>of</strong> a Newtonian fluid the stress τ = µ∂u/∂y. Hence eqn 6.16<br />

becomes<br />

δp∗ �<br />

∂<br />

= µ<br />

δx ∂y<br />

∂u<br />

�<br />

∂y<br />

(6.17)<br />

As p∗ nowhere varies in the y direction, δp∗ /δx is independent <strong>of</strong> y and<br />

eqn 6.17 may be integrated with respect to y:<br />

δp∗ y = µ∂u + A<br />

δx ∂y<br />

If µ is constant, a further integration with respect to y gives<br />

�<br />

δp∗ �<br />

y2 = µu + Ay + B (6.18)<br />

δx 2<br />

Since the portion <strong>of</strong> fluid studied is very far from the edges <strong>of</strong> the planes,<br />

A and B are constants, independent <strong>of</strong> both x and z.<br />

To determine these constants the boundary conditions must be considered.<br />

If both the planes are stationary the velocity <strong>of</strong> the fluid in contact with each

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