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Mechanics of Fluids

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For example, the parameter Fϱ/µ 2 is independent <strong>of</strong> d, and u, so<br />

experimental results in which either d, oru, are varied can be analysed in a<br />

very straightforward way by plotting F against d, oru. At the interpretation<br />

stage the grounds <strong>of</strong> convenience can again be invoked. Experience shows<br />

that F/(ϱu 2 d 2 ) varies only slowly with Re at large values <strong>of</strong> Re, and so the<br />

functional form (5.13) should be used at high Reynolds numbers. At low<br />

values <strong>of</strong> Re, the parameter F/µud is constant or varies only slightly with<br />

Re, and so the form (5.14) is the obvious choice at low Reynolds numbers.<br />

The second consideration is to use what are regarded as traditional forms <strong>of</strong><br />

dimensionless groups. For example, the dimensionless group µ/(duϱ) <strong>of</strong>ten<br />

arises from the process <strong>of</strong> dimensional analysis. This should be recognised<br />

as the reciprocal <strong>of</strong> Reynolds number, by which it should be replaced.<br />

We conclude this Section by noting that it is sometimes desirable to<br />

reformulate a dimensional analysis to eliminate a specific variable from a<br />

dimensionless group, <strong>of</strong>ten the one containing the dependent variable. This<br />

can be done by creating an alternative dimensionless group. Consider the<br />

dimensionless groups NA and NB related by the expression NA = φ(NB). If<br />

there is a variable common to NA and NB, then that variable can be eliminated<br />

between NA and NB by creating a new dimensionless group NC. Writing<br />

NC = NA · (NB) δ , the value <strong>of</strong> δ can be selected to eliminate the chosen variable,<br />

resulting in the functional relation NC = ψ(NB). As an example <strong>of</strong><br />

this process, define NA = F/(ϱu 2 d 2 ) and NB = ϱud/µ, and assume that<br />

we wish to eliminate the variable ϱ. Write NC = (F/(ϱu 2 d 2 )) · (ϱud/µ) δ .By<br />

inspection δ = 1 and hence NC = F/µud.<br />

Example 5.2 The flow rate through differential-pressure flowmetering<br />

devices, such as venturi and orifice-plate meters, can be<br />

calculated when the value <strong>of</strong> the discharge coefficient is known.<br />

Information on the discharge coefficient is conventionally presented<br />

as a function <strong>of</strong> the Reynolds number.<br />

(a) Shown that this method <strong>of</strong> presenting the data is inconvenient for<br />

many purposes.<br />

(b) By using different dimensionless parameters, show that these<br />

difficulties can be avoided.<br />

Solution<br />

Define the mean velocities in the pipe and at the throat by u1 and<br />

u2, and the upstream pipe diameter and throat diameter by D and d,<br />

respectively.<br />

(a) Reference to Chapter 3 shows that the discharge coefficient, C,<br />

is defined as<br />

C =<br />

Q<br />

E(π/4)d2 �<br />

where E ={1 − (d/D) 4 } −1/2 .<br />

1<br />

2g�h =<br />

Q<br />

E(π/4)d2 �<br />

ϱ<br />

2�p<br />

Dimensional analysis 177

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