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Mechanics of Fluids

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136 The momentum equation<br />

=<br />

=<br />

� �<br />

−<br />

ABCD<br />

� �<br />

ABCD<br />

� �<br />

DCC ′ D ′<br />

uxδm − �<br />

uxδm<br />

ABB ′ A ′<br />

�<br />

before δt<br />

uxδm − �<br />

ABB ′ A ′<br />

uxδm + �<br />

uxδm<br />

�<br />

DCC ′ D ′<br />

after δt<br />

uxδm<br />

�<br />

after δt<br />

since, as the flow is assumed steady, �� uxδm �<br />

is the same after δt as<br />

ABCD<br />

before δt. Thus, during the time intereval δt, the increase <strong>of</strong> x-momentum<br />

<strong>of</strong> the batch <strong>of</strong> fluid considered is equal to the x-momentum leaving the<br />

stream-tube in that time minus the x-momentum entering in that time:<br />

� � � �<br />

�<br />

�<br />

uxδm − uxδm<br />

DCC ′ D ′<br />

ABB ′ A ′<br />

For a very small value <strong>of</strong> δt the distances AA ′ , BB ′ are very small, so<br />

the values <strong>of</strong> ux, for all the particles in the space ABB ′ A ′ are substantially<br />

the same. Similarly, all particles in the space DCC ′ D ′ have substantially the<br />

same value <strong>of</strong> ux, although this may differ considerably from the value for<br />

particles in ABB ′ A ′ . The ux terms may consequently be taken outside the<br />

summations.<br />

Therefore the increase <strong>of</strong> x-momentum during the interval δt is<br />

� �<br />

� �<br />

δm<br />

δm<br />

�<br />

ux<br />

DCC ′ −<br />

D ′<br />

�<br />

ux<br />

ABB ′ A ′<br />

(4.1)<br />

Now �� δm �<br />

DCC ′ D ′ is the mass <strong>of</strong> fluid which has crossed the plane CD<br />

during the interval δt and so is expressed by ˙mδt, where ˙m denotes the rate<br />

<strong>of</strong> mass flow. Since the flow is steady, �� δm �<br />

ABB ′ A ′ also equals ˙mδt. Thus<br />

expression 4.1 may be written ˙m(ux2 − ux1 )δt, where suffix 1 refers to the<br />

inlet section <strong>of</strong> the stream-tube, suffix 2 to the outlet section. The rate <strong>of</strong><br />

increase <strong>of</strong> x-momentum is obtained by dividing by δt, and the result, by<br />

Newton’s Second Law, equals the net force Fx on the fluid in the x direction<br />

Fx = ˙m(ux2 − ux1 ) (4.2)<br />

The corresponding force in the x direction exerted by the fluid on its<br />

surroundings is, by Newton’s Third Law, −Fx.<br />

A similar analysis for the relation between force and rate <strong>of</strong> increase <strong>of</strong><br />

momentum in the y direction gives<br />

Fy = ˙m(uy2 − uy1 ) (4.3)<br />

In steady flow ˙m is constant and so ˙m = ϱ1A1u1 = ϱ2A2u2 where ϱ represents<br />

the density <strong>of</strong> the fluid and A the cross-sectional area <strong>of</strong> the stream-tube<br />

(A being perpendicular to u).<br />

We have so far considered only a single stream-tube with a cross-sectional<br />

area so small that the velocity over each end face (AB, CD) may be considered<br />

uniform. Let us now consider a bundle <strong>of</strong> adjacent stream-tubes, each <strong>of</strong><br />

cross-sectional area δA, which together carry all the flow being examined.

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