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Mechanics of Fluids

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492 Compressible flow <strong>of</strong> gases<br />

For gases the gz term in eqns 11.8–11.11 can be omitted as negligible<br />

compared with the remaining terms because ρ is small and changes <strong>of</strong> z are<br />

usually small also. (The concept <strong>of</strong> piezometric pressure p + ρgz cannot <strong>of</strong><br />

course be used where the density is variable.) Equation 11.9 may then be<br />

reduced to<br />

h + 1<br />

2 u2 = constant along a streamline SF, A (11.12)<br />

It is clear from eqn 11.12 that in steady adiabatic flow an increase <strong>of</strong><br />

velocity must be accompanied by a decrease <strong>of</strong> enthalpy and a decrease<br />

<strong>of</strong> velocity by an increase <strong>of</strong> enthalpy. For a given streamline the specific<br />

enthalpy is a maximum when the velocity is zero (at a stagnation point), and<br />

this maximum value is termed the stagnation enthalpy, h0. From eqn 11.7<br />

the corresponding stagnation temperature T0 is h0/cp and so the energy<br />

equation may be written<br />

cpT + 1<br />

2 u2 = cpT0 SF, A, PG (11.13)<br />

If an attempt is made to measure the temperature <strong>of</strong> a flowing gas by placing<br />

a thermometer or similar device in the stream, the temperature recorded will<br />

be greater than T. Equation 11.13 shows that the stagnation temperature<br />

exceeds T by u 2 /2cp. For air cp = 1005 J · kg −1 · K −1 and so the stagnation<br />

temperature for an air stream at, say, 200 m · s −1 exceeds the ordinary<br />

static temperature by about 20 K. And the nose cone <strong>of</strong> a rocket travelling<br />

through air at, say, 2 km · s −1 must withstand a temperature rise approaching<br />

2000 K! For these extreme conditions the use <strong>of</strong> eqn 11.13 involves<br />

some inaccuracy because <strong>of</strong> the variation <strong>of</strong> cp during the large increases<br />

<strong>of</strong> temperature and pressure. However, although the stagnation temperature<br />

would be reached at the stagnation point on a thermometer bulb, the<br />

temperature would rise less at other points on it, so the mean temperature<br />

recorded by an ordinary thermometer would be somewhat less then the stagnation<br />

temperature. The static temperature cannot be directly measured by<br />

any stationary instrument. (It could be measured only by a thermometer or<br />

other instrument moving at the same velocity as the gas.)<br />

Example 11.1 Air flows adiabatically through a pipe. At a plane,<br />

denoted by suffix 1, the temperature is −2 ◦ C, its pressure is 1.50 ×<br />

10 5 N · m −2 , and the air moves at a speed <strong>of</strong> 270 m · s −1 . At plane 2 the<br />

pressure is 1.20 × 10 5 N · m −2 and the speed <strong>of</strong> the air is 320 m · s −1 .<br />

Calculate the following properties <strong>of</strong> the air:<br />

(a) the density at plane 1<br />

(b) the stagnation temperature<br />

(c) the temperature and density at plane 2.

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