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Mechanics of Fluids

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378 The flow <strong>of</strong> an inviscid fluid<br />

Fig. 9.18<br />

two streamlines shown in Fig. 9.18, the flow being assumed steady. At radius<br />

R from the centre <strong>of</strong> curvature the pressure is p, at radius R + δR it is p + δp;<br />

consequently there is a net thrust on the element, towards the centre <strong>of</strong><br />

curvature, equal to<br />

(p + δp)(R + δR)δθ − pRδθ − 2<br />

�<br />

p + δp<br />

�<br />

δR sin<br />

2<br />

δθ<br />

2<br />

(for unit thickness perpendicular to the diagram). As δθ → 0, sin(δθ/2) →<br />

δθ/2 and, with higher orders <strong>of</strong> small magnitudes neglected, the thrust<br />

reduces to Rδpδθ. (Shear forces, even if present, have no component<br />

perpendicular to the streamlines.)<br />

The component <strong>of</strong> the weight acting radially inwards<br />

= RδθδRϱg (δz/δR) = Rϱg δθ δz<br />

where δz is the vertical projection <strong>of</strong> δR so that arccos (δz/δR) is the angle<br />

between the radius and the vertical. Thus the total inward force is<br />

Rδpδθ + Rϱgδθδz = Mass × Centripetal acceleration<br />

Division by Rϱgδθ gives<br />

= ϱRδθδR(q 2 /R)<br />

δp q2 δR<br />

+ δz =<br />

ϱg R g<br />

Now, by Bernoulli’s theorem for steady flow <strong>of</strong> a frictionless fluid:<br />

p q2<br />

+ + z = H<br />

ϱg 2g<br />

(9.16)<br />

where H is a constant along a streamline (although it may differ from one<br />

streamline to another). Differentiation gives<br />

δp 2qδq<br />

+ + δz = δH (9.17)<br />

ϱg 2g

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