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String Theory Demystified

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CHAPTER 5 Conformal Field <strong>Theory</strong> Part I<br />

We’ve shown that Eq. (5.14) is an equivalent way to write the Polyakov action.<br />

But it’s much simpler, and it’s much simpler to derive the equations of motion using<br />

this form. We can do this by varying the action [Eq. (5.14)] with respect to the<br />

coordinate X µ. This is done by letting X → X + δ X . Then<br />

µ µ µ<br />

1 2 µ<br />

1 2 µ<br />

S→d z∂X ∂ X + X = d z∂X ∂ X +∂<br />

2 ′ ∫ ( µ δ µ )<br />

πα<br />

2πα<br />

′ ∫ ( µ δ Xµ<br />

)<br />

1 2 µ 1 2 µ<br />

= dz∂X∂ Xµ + dz∂X( ∂ δXµ ) = S+<br />

δ<br />

2πα<br />

′ ∫ 2πα<br />

′ ∫<br />

S<br />

We can obtain the equations of classical motion by requiring that δS = 0. Integrating<br />

by parts and discarding the boundary term:<br />

1 2 µ<br />

δS<br />

= d z X δ Xµ<br />

πα ′ ∫ ∂ ( ∂ )<br />

2<br />

1 2 µ<br />

=− dz∂∂X δ Xµ<br />

2πα<br />

′ ∫ ( )<br />

We have used the fact that partial derivatives commute. This term must vanish<br />

for the action to be invariant. Therefore it must be the case that<br />

97<br />

µ<br />

∂∂ X (, z z)<br />

= 0 (5.15)<br />

µ µ<br />

We’ve written X = X (, z z)to<br />

emphasize that in general the coordinates can be<br />

a function of z and z.<br />

However, as you might guess from your studies of complex<br />

variables there is a special case of interest, that of analytic or holomorphic functions.<br />

A function f (, z z)is<br />

holomorphic if<br />

That is, f = f( z)<br />

only. On the other hand, if<br />

∂<br />

∂ =<br />

f<br />

0 (5.16)<br />

z<br />

∂<br />

∂ =<br />

f<br />

0 (5.17)<br />

z<br />

and f = f( z),<br />

then we say that f is antiholomorphic. In string theory, if ∂( ∂ X ) =<br />

µ<br />

0<br />

then ∂X µ is a holomorphic function which is called left moving. In the other case,<br />

where ∂( ∂ X ) =<br />

µ<br />

0 , the function ∂X µ is antiholomorphic and is called right moving.

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