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String Theory Demystified

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80 <strong>String</strong> <strong>Theory</strong> Demystifi ed<br />

∞<br />

Σ<br />

=<br />

It follows that D/ 2 n= D/ 2( − 1/ 12) =−D/<br />

24.<br />

Another undetermined constant<br />

n 1<br />

piece is missing from the difference between the general expression of L0 and the<br />

normal ordered expression of L0 . This is a normal ordering constant which is<br />

denoted by a. Therefore in any calculation L0 is replaced by L0− a,<br />

where a is a<br />

constant.<br />

The point of all this is to write down the commutation relations for the Virasoro<br />

operators. Using Eq. (4.10), one fi nds that<br />

D 3<br />

[ Lm, Ln] = ( m− n) Lm+<br />

n+ ( m −m)<br />

δm+<br />

n,<br />

12<br />

0<br />

(4.20)<br />

We call this commutation relation the Virasoro algebra with central extension.<br />

The central charge is the space-time dimension D which has shown up in the second<br />

term on the right-hand side. This is also the number of free scalar fi elds on the<br />

worldsheet. It is clear that if m = 0, ± 1 the central extension term will vanish. This<br />

singles out L1, L0, and L−1which<br />

form a closed subalgebra. We call this the SL<br />

(2, R) algebra.<br />

The Virasoro operators can be used to eliminate unphysical states (i.e., negative<br />

norm states) from the theory by requiring that the expectation value of L0a −<br />

vanishes for a physical state ψ . That is, we impose the constraint<br />

ψ L − aδ<br />

ψ = 0<br />

m m,0<br />

for m ≥ 0. The term aδ m,0<br />

takes care of the fact that we only need the normal<br />

ordering constant a in the case of L0 . To eliminate negative norm states, specifi c<br />

conditions must be put on a and D, which is the origin of the “extra dimensions”<br />

in string theory. In particular, it can be shown that negative norm states can be<br />

eliminated if<br />

a= 1 D=<br />

26 (4.21)<br />

The reason that a = 1is chosen is a bit beyond the scope we want to cover in this<br />

book, see the references if interested in the proof.<br />

We can proceed further to obtain a mass operator. First recall that Einstein’s<br />

equation tells us<br />

µ 2 2 µ<br />

p p + m = 0<br />

⇒ m =−p<br />

p<br />

µ<br />

µ

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