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String Theory Demystified

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CHAPTER 13 D-Branes 225<br />

Once again we apply the quantization procedure, considering the bosonic string<br />

theory case. The fi rst step is to write down the modal expansions. These will be<br />

different depending on which coordinates we look at because now we have NN<br />

coordinates and DD coordinates. The fi rst step is to write out the modal<br />

expansions.<br />

Now let’s recall the open string modal expansion, which can be written in the<br />

following way:<br />

µ<br />

µ µ µ<br />

αn<br />

−inτ<br />

X ( στ , ) = x + 2α′ p τ+ i 2 α′<br />

∑ e cos( nσ)<br />

(13.9)<br />

0 0<br />

n≠<br />

n<br />

Taking the derivative of this expression with respect to σ we fi nd<br />

Clearly this expression satisfi es<br />

∑<br />

µ µ −inτ<br />

∂ X ( στ , ) =− i 2α<br />

σ<br />

′ α e sin( nσ)<br />

n<br />

n≠0<br />

µ<br />

∂ X 0 = 0<br />

σ<br />

σ= , π<br />

which are the Neumann boundary conditions. So, we take the modal expansion for<br />

the X i to be<br />

i<br />

i i i αn<br />

−inτ<br />

X ( στ , ) = x + 2α′ p τ+ i 2 α′<br />

∑ e cos( nσ)<br />

(13.10)<br />

0 0<br />

n≠<br />

n<br />

For the DD coordinates, we really have two requirements that have to be satisfi ed.<br />

We need the summation over the modes ∑ in the expansion to vanish at σ = 0, π.<br />

n≠0 This indicates that we should use sin( nσ ) instead of cos( nσ ) which is in the<br />

a a a<br />

usual open string expansion. However, we also need X ( 0, τ) = X ( π, τ)<br />

= x .<br />

Looking at the usual modal expansion, this tells us that we must take<br />

x → x 0<br />

a<br />

p → 0<br />

a a<br />

0<br />

0<br />

0<br />

Quantization

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