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String Theory Demystified

String Theory Demystified

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CHAPTER 4 <strong>String</strong> Quantization<br />

Using Eqs. (4.3) and (4.8) together with our previous result, we have<br />

2 ∞ s − i( m+ n)<br />

τ − i mσ+ nσ<br />

′ µ ν<br />

∑ e e αm αm<br />

2 mn , =−∞<br />

( ) iη<br />

[ , ] =<br />

2T<br />

µν<br />

µν<br />

iη<br />

⎛ i<br />

= −<br />

2T⎝ ⎜<br />

2π<br />

µν<br />

= η<br />

2<br />

∂<br />

δσ ( − σ′<br />

)<br />

∂σ<br />

1<br />

2πT me im<br />

∞<br />

− ( σ− σ′<br />

)<br />

∑<br />

m=−∞<br />

∞<br />

− σ− σ′<br />

me im(<br />

)<br />

∑<br />

m=−∞<br />

We have also used Eq. (2.50) to relate s and the string tension T. This gives us<br />

the commutation relation for the modes<br />

µ ν µν<br />

⎡⎣ αm, α ⎤ n⎦ = η mδm+<br />

n,<br />

0<br />

µ ν<br />

Equation (4.5) can be used to show that the αm and α commute. We can write all<br />

n<br />

of the commutation relations for the modes of the closed string as<br />

µ ν µν µ ν µν<br />

⎡⎣ α , α ⎤⎦ = mη δ ⎡⎣ α , α ⎤⎦ = mη<br />

δ<br />

µ ν<br />

m n m+ n, 0 m n m+<br />

n, 0<br />

m n<br />

⎞<br />

⎠<br />

⎟<br />

75<br />

⎡⎣ α , α ⎤⎦ = 0 (4.9)<br />

In the chapter quiz you will also derive a commutation relation for the center-ofmass<br />

position and momentum of the string<br />

[ x , p ] = iη<br />

µ ν µν<br />

COMMUTATION RELATIONS FOR THE OPEN STRING<br />

µ ν µν<br />

In the case of the open string, it can be shown that together with [ x , p ] = iη,<br />

the<br />

commutation relations are<br />

THE OPEN STRING SPECTRUM<br />

µ ν µν<br />

⎡⎣ α α ⎤⎦ = mη<br />

δ + 0 (4.10)<br />

m, n m n,<br />

With the commutation relations in hand, we can proceed to fi nd the states of the<br />

string. Because the open string case is simpler, we consider this fi rst. Notice that in<br />

our quantization procedure where we have imposed commutation relations on the

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