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String Theory Demystified

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76 <strong>String</strong> <strong>Theory</strong> Demystifi ed<br />

µ ν<br />

modes αm (and αn<br />

for the closed string), what we have done is promote them to<br />

operators. By extension, since the X µ ( σ, τ)are<br />

defi ned in terms of α µ<br />

m, the X µ ( σ, τ)<br />

are now to be thought of as operators as well. Therefore the next task in our program<br />

is to determine the state space of the system, that is the states upon which the α µ<br />

m and<br />

by extension the X µ ( σ, τ)<br />

act. This procedure is really pretty similar to what you’re<br />

used to from your previous studies of quantum theory.<br />

The fi rst item to notice is that the commutation relations have some similarity to<br />

the harmonic oscillator you learned about in fi rst semester quantum mechanics.<br />

Temporarily dispensing with our convention of setting = 1, recall that we can<br />

defi ne the creation and annihilation operators for the harmonic oscillator as<br />

† m i<br />

m i<br />

aˆ<br />

xˆ<br />

pˆ aˆ<br />

xˆ<br />

ˆ<br />

m m p<br />

ω ⎛<br />

= −<br />

⎞<br />

ω ⎛<br />

⎝<br />

⎜<br />

⎠<br />

⎟ = +<br />

⎞<br />

⎝<br />

⎜<br />

⎠<br />

⎟<br />

2 ω<br />

2<br />

ω<br />

These operators satisfy the commutation relation:<br />

The hamiltonian of the system is given by<br />

†<br />

[ aˆ, a ˆ ] = 1 (4.11)<br />

ˆ ⎛ † 1<br />

H = ω aˆ aˆ+<br />

⎞<br />

⎝ 2⎠<br />

We introduce the number operator ˆ †<br />

N = aˆ aˆ<br />

which has eigenstates n :<br />

ˆN n = nn<br />

(4.12)<br />

where n = 012 , , ,.... A system consisting of an infi nite collection of harmonic<br />

oscillators is called a fock space.<br />

Continuing, the number operator and its eigenstates allow us to write down the<br />

quantized energy levels of the harmonic oscillator, which are given by<br />

ˆ ⎛<br />

Hn Nˆ 1⎞<br />

⎛ 1⎞<br />

= ω + n n n Enn ⎝<br />

⎜<br />

⎠<br />

⎟ = ω<br />

+<br />

⎝<br />

⎜<br />

⎠<br />

⎟ =<br />

2<br />

2<br />

You should also recall that the system has a ground state, which is the lowest<br />

possible energy state. This is denoted by 0 .<br />

A comparison of Eqs. (4.9) and (4.11) indicates that we have a similar system in<br />

the case of the string. This should not be surprising, since what else would you

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