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String Theory Demystified

String Theory Demystified

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CHAPTER 7 RNS Superstrings 141<br />

OPEN STRING BOUNDARY CONDITIONS<br />

When varying the action, the boundary terms must vanish in order to maintain<br />

Lorentz invariance. In the case of open string, the boundary terms σ = 0 and σ = π<br />

must both vanish independently. We can obtain<br />

at σ = 0 if we take<br />

ψδψ− ψδψ=0<br />

+ + − −<br />

+ −<br />

ψ ( 0, τ) = ψ ( 0 , τ)<br />

(7.25)<br />

µ µ<br />

Now in general, ψ =± ψ will make the boundary terms vanish, but typical convention<br />

+ −<br />

is to fi x the boundary condition at σ = 0 using Eq. (7.25). This leaves the choice of<br />

sign at σ = π ambiguous. Depending on the sign we choose, we obtain two different<br />

boundary conditions. Ramond or R boundary conditions are given by the choice<br />

+ −<br />

ψ ( π , τ) = ψ ( π , τ)<br />

(Ramond) (7.26)<br />

µ µ<br />

The other choice we can make is known as Neveau-Schwarz or NS boundary<br />

conditions:<br />

+ −<br />

ψ ( π , τ) =−ψ<br />

( π , τ)<br />

(Neveau-Schwarz) (7.27)<br />

µ µ<br />

We often refer to the boundary conditions chosen as the sector. The choice of<br />

boundary conditions has dramatic consequences. In particular<br />

• The R sector gives rise to string states that are space-time fermions.<br />

• The NS sector gives rise to string states that are space-time bosons.<br />

OPEN STRING MODE EXPANSIONS<br />

We consider the R sector fi rst. The mode expansions are<br />

µ 1 µ −in( τ−σ) ψ−( σ, τ)<br />

= ∑ dne 2 n<br />

µ 1 µ −in(<br />

τ+ σ)<br />

ψ+ ( σ, τ)<br />

= ∑ dne 2<br />

n<br />

(7.28)

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