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String Theory Demystified

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CHAPTER 5 Conformal Field <strong>Theory</strong> Part I<br />

Using w= z/( 1 + az)<br />

we get<br />

z<br />

w<br />

T w<br />

az<br />

b ( ) = =<br />

1+<br />

1+<br />

bw ⎛ z ⎞<br />

1+<br />

b<br />

⎝<br />

⎜<br />

+ az⎠<br />

⎟<br />

1<br />

z<br />

=<br />

⎛ ⎛ z ⎞⎞<br />

( 1+ az) 1+<br />

b<br />

⎝<br />

⎜<br />

1+<br />

⎠<br />

⎟<br />

⎝<br />

⎜<br />

az ⎠<br />

⎟<br />

z z<br />

= = = Ta+ b(<br />

z<br />

1+ az + bz 1+<br />

( a+ b) z<br />

Hence, T () z = z/( 1+ az)<br />

satisfi es the group composition property.<br />

a<br />

)<br />

103<br />

EXAMPLE 5.3<br />

Let Ta () z = z/( 1 + az)<br />

and suppose that a is real and a = 1. Determine the generators<br />

of this transformation.<br />

SOLUTION<br />

n+1<br />

Recall that the generators have the form n =−z ∂zand<br />

similarly for the complex<br />

conjugate. This form holds for an infi nitesimal transformation parameter<br />

n<br />

ε( z) =−∑ anz +1 . So we can deduce the expressions for the generators by writing<br />

the transformation as a series.<br />

Consider the following series<br />

Now multiply by r to give<br />

s= 1−<br />

r+ r − r +<br />

2 3 <br />

2 3 4<br />

rs = r − r + r − r + <br />

Now add both series. On the left side we obtain s+ rs= s( 1 + r)<br />

. On the right, we<br />

have<br />

2 3 2 3 4<br />

s+ rs= 1− r+ r − r + + r− r + r − r + =<br />

1

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