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String Theory Demystified

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CHAPTER 6 BRST Quantization 123<br />

To write down the total Virasoro operator for the “real” fi elds + ghost fi elds, we<br />

form a sum of the respective operators. That is<br />

tot<br />

gh<br />

L L L a<br />

m<br />

= m + m − δ m,0<br />

where the last term on the right is the normal-ordering constant for m = 0. It can be<br />

shown that the commutation relation for the total Virasoro operator is of the form:<br />

tot tot<br />

tot<br />

⎡⎣ Lm, Ln⎤⎦ = ( m− n) Lm+ n+<br />

A( m)<br />

m+ n,<br />

δ 0<br />

Notice that the presence of the term Am ( ) on the right keeps us from obtaining a<br />

relation that preserves the classical Virasoro algebra. As such, this term is called an<br />

anomaly. The anomaly is determined in terms of two unknown constants which you<br />

might guess by now are D and a. It has the form<br />

D 2 1<br />

3<br />

Am ( ) = mm ( − 1)<br />

+ ( m− 13m ) + 2am<br />

12<br />

6<br />

To make the anomaly vanish, we take D= 26, a=<br />

1,<br />

which is consistent with the<br />

other results obtained so far in the book for bosonic string theory.<br />

The BRST current is given by<br />

1 gh 3 2<br />

j= cT + : cT : + ∂ c<br />

2 2<br />

The BRST charge is given by the mode expansion:<br />

1<br />

Q= ∑ cnL−n + ∑ ( m−n): cmcnb−m−n : −c<br />

2<br />

n<br />

mn ,<br />

Using tedious algebra one can show that<br />

2 1 tot tot<br />

tot 1<br />

Q = ∑ ( ⎡LmLnm n Lm n c mc n<br />

2<br />

⎣ , ⎤⎦ −( − ) + ) − − ≈ ( D − 26)<br />

12<br />

Hence the requirement that Q 2<br />

= 0 forces us to take D = 26.<br />

Going back to the original BRST approach outlined in Eqs. (6.1) to (6.5), using<br />

the classical algebra for the Virasoro operators:<br />

[ Lm, Ln] = ( m− n) Lm+<br />

n<br />

0

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