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String Theory Demystified

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102 <strong>String</strong> <strong>Theory</strong> Demystifi ed<br />

Hence we conclude that<br />

[ , ] = ( m− n)<br />

+<br />

m n m n<br />

The generators 0, ± 1and 0,<br />

± 1are<br />

a special case. Consider the action of these<br />

generators on the infi nitesimal coordinate transformations [Eq. (5.21)]. Taking<br />

n =−101 , , we have<br />

n=− 1:<br />

z′ = z−ε(translation)<br />

n= 0 : z′ = z−εz (scaling)<br />

2<br />

n= 1:<br />

z′ = z−εz (special conformal transformation)<br />

There are similar expressions for the complex conjugates. Hence −1 and −1<br />

generate translation, 0 and 0, ( 0 + 0)<br />

generate scaling and dilations, respectively,<br />

i( 0 − 0)<br />

generates rotations, and 1 and 1generate<br />

special conformal transformations.<br />

All together, the transformations generated by 0, ± 1 and 0,<br />

± 1can<br />

be written in<br />

the form<br />

az + b<br />

z→ γ () z =<br />

(5.25)<br />

cz + d<br />

Here, ad − bc =1 and the transformation γ () z is called a Möbius transformation.<br />

EXAMPLE 5.2<br />

Consider the transformation Ta () z = z/( + az)<br />

1 . Show that Ta z () constitutes a<br />

transformation group by examining the composition Tb( Ta( z)).<br />

SOLUTION<br />

This is actually a simple problem. We need to show that<br />

z<br />

Tb( Ta( z)) = Ta+ b(<br />

z)<br />

=<br />

1+<br />

( a+ b) z<br />

Starting with T () z = z/( 1 + az)<br />

, let w= z/( 1 + az)<br />

. Now<br />

a<br />

w<br />

Tb w<br />

bw<br />

( )= 1+

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