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PhD Fekete - SZIE version - 2.2 - Szent István Egyetem

PhD Fekete - SZIE version - 2.2 - Szent István Egyetem

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Literature review<br />

They applied the following simplifications:<br />

Figure 2.53. Numerical model [Ling et al., 1997]<br />

a) The model is planar, created in the sagittal plane,<br />

b) Ligaments are one-dimensional bodies without mass,<br />

c) Ligaments can change in length, but only in case of tension,<br />

d) No penetration of the tibia or femur is allowed,<br />

e) No friction is assumed.<br />

As an incompleteness of the earlier models, the authors appointed that the articular surfaces of<br />

the femur are often assumed circular. To improve this problem, they used fourth order and root<br />

functions to describe the connecting surfaces (denoted by f i parameter). The authors determined<br />

the sliding-rolling ratio by calculating the arc lengths travelled on the surface of the tibia and<br />

femur between each simulation step:<br />

s =<br />

upper<br />

∫<br />

lower<br />

2<br />

⎛ dfi<br />

⎞<br />

1 + ⎜ ⎟ dx<br />

(2.12)<br />

⎝ dx ⎠<br />

If i = 1, then it is the curve of the tibia, if i = 2, then it is the curve of the femur. The slidingrolling<br />

ratio is defined as the difference between the larger distance (s l ) and the smaller distance<br />

(s s ) travelled on the femur and tibia over the smaller of the two arc lengths travelled (s s ).<br />

sliding<br />

s − s<br />

s<br />

l s<br />

/ rolling =<br />

(2.13)<br />

The problem with this definition is that e.g.: s l equals to 6 mm and s s equals to 2 mm, then if we<br />

calculate the sliding-rolling ratio from Eq. (2.13), we obtain 2. By knowing s l and s s , then by<br />

common sense it is obvious that the sliding-rolling ratio is distributed as 66% sliding and 33%<br />

of rolling. However, from the above-mentioned formula (Eq. (2.13)), we can only obtain the<br />

number of two, which grants no clear physical interpretation about the ratio.<br />

s<br />

– 56 –

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