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John Stillwell - Naive Lie Theory.pdf - Index of

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98 5 The tangent space<br />

as in ordinary calculus. (This can be checked by differentiating the series<br />

for e tX .) It follows that A(t) has the tangent vector A ′ (0) =X at 1, and<br />

therefore each X such that X +X T = 0 occurs as a tangent vector to SO(n)<br />

at 1, as required.<br />

□<br />

As mentioned in the previous section, a matrix X such that X +X T = 0<br />

is called skew-symmetric. Important examples are the 3 × 3 skewsymmetric<br />

matrices, which have the form<br />

⎛<br />

0 −x<br />

⎞<br />

−y<br />

X = ⎝x 0 −z⎠.<br />

y z 0<br />

Notice that sums and scalar multiples <strong>of</strong> these skew-symmetric matrices<br />

are again skew-symmetric, so the 3 × 3 skew-symmetric matrices form a<br />

vector space. This space has dimension 3, as we would expect, since it is<br />

the tangent space to the 3-dimensional space SO(3). Less obviously, the<br />

skew-symmetric matrices are closed under the <strong>Lie</strong> bracket operation<br />

[X 1 ,X 2 ]=X 1 X 2 − X 2 X 1 .<br />

Later we will see that the tangent space <strong>of</strong> any <strong>Lie</strong> group G is a vector space<br />

closed under the <strong>Lie</strong> bracket, and that the <strong>Lie</strong> bracket reflects the conjugate<br />

g 1 g 2 g −1<br />

1<br />

<strong>of</strong> g 2 by g −1<br />

1<br />

∈ G. This is why the tangent space is so important<br />

in the investigation <strong>of</strong> <strong>Lie</strong> groups: it “linearizes” them without obliterating<br />

much <strong>of</strong> their structure.<br />

Exercises<br />

According to the theorem above, the tangent space <strong>of</strong> SO(3) consists <strong>of</strong> 3 × 3 real<br />

matrices X such that X = −X T . The following exercises study this space and the<br />

<strong>Lie</strong> bracket operation on it.<br />

5.2.1 Explain why each element <strong>of</strong> the tangent space <strong>of</strong> SO(3) has the form<br />

⎛ ⎞<br />

0 −x −y<br />

X = ⎝x 0 −z⎠ = xI + yJ + zK,<br />

y z 0<br />

where<br />

⎛<br />

I = ⎝ 0 −1 0 ⎞ ⎛<br />

1 0 0⎠, J = ⎝ 0 0 −1 ⎞ ⎛<br />

0 0 0 ⎠, K = ⎝ 0 0 0 ⎞<br />

0 0 −1⎠.<br />

0 0 0 1 0 0<br />

0 1 0

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