John Stillwell - Naive Lie Theory.pdf - Index of
John Stillwell - Naive Lie Theory.pdf - Index of
John Stillwell - Naive Lie Theory.pdf - Index of
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98 5 The tangent space<br />
as in ordinary calculus. (This can be checked by differentiating the series<br />
for e tX .) It follows that A(t) has the tangent vector A ′ (0) =X at 1, and<br />
therefore each X such that X +X T = 0 occurs as a tangent vector to SO(n)<br />
at 1, as required.<br />
□<br />
As mentioned in the previous section, a matrix X such that X +X T = 0<br />
is called skew-symmetric. Important examples are the 3 × 3 skewsymmetric<br />
matrices, which have the form<br />
⎛<br />
0 −x<br />
⎞<br />
−y<br />
X = ⎝x 0 −z⎠.<br />
y z 0<br />
Notice that sums and scalar multiples <strong>of</strong> these skew-symmetric matrices<br />
are again skew-symmetric, so the 3 × 3 skew-symmetric matrices form a<br />
vector space. This space has dimension 3, as we would expect, since it is<br />
the tangent space to the 3-dimensional space SO(3). Less obviously, the<br />
skew-symmetric matrices are closed under the <strong>Lie</strong> bracket operation<br />
[X 1 ,X 2 ]=X 1 X 2 − X 2 X 1 .<br />
Later we will see that the tangent space <strong>of</strong> any <strong>Lie</strong> group G is a vector space<br />
closed under the <strong>Lie</strong> bracket, and that the <strong>Lie</strong> bracket reflects the conjugate<br />
g 1 g 2 g −1<br />
1<br />
<strong>of</strong> g 2 by g −1<br />
1<br />
∈ G. This is why the tangent space is so important<br />
in the investigation <strong>of</strong> <strong>Lie</strong> groups: it “linearizes” them without obliterating<br />
much <strong>of</strong> their structure.<br />
Exercises<br />
According to the theorem above, the tangent space <strong>of</strong> SO(3) consists <strong>of</strong> 3 × 3 real<br />
matrices X such that X = −X T . The following exercises study this space and the<br />
<strong>Lie</strong> bracket operation on it.<br />
5.2.1 Explain why each element <strong>of</strong> the tangent space <strong>of</strong> SO(3) has the form<br />
⎛ ⎞<br />
0 −x −y<br />
X = ⎝x 0 −z⎠ = xI + yJ + zK,<br />
y z 0<br />
where<br />
⎛<br />
I = ⎝ 0 −1 0 ⎞ ⎛<br />
1 0 0⎠, J = ⎝ 0 0 −1 ⎞ ⎛<br />
0 0 0 ⎠, K = ⎝ 0 0 0 ⎞<br />
0 0 −1⎠.<br />
0 0 0 1 0 0<br />
0 1 0