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Integral Solutions of the Homogeneous Cubic Equation<br />

which is satisfied by<br />

v m<br />

v m<br />

2<br />

2<br />

2<br />

2 2<br />

n , p 2mn,<br />

X m n <br />

m<br />

n o<br />

2<br />

2 2<br />

n , p m n , X 2mn<br />

(5)<br />

Substituting (5) in (2) , the two sets of solutions satisfying (1) are obtained as follows:<br />

SET 1:<br />

x(<br />

u,<br />

m,<br />

n)<br />

u m<br />

y(<br />

u,<br />

m,<br />

n)<br />

u m<br />

z(<br />

u,<br />

m,<br />

n)<br />

u 2mn<br />

w(<br />

u,<br />

m,<br />

n)<br />

u 2mn<br />

X ( m,<br />

n)<br />

m<br />

2<br />

n<br />

2<br />

2<br />

2<br />

n<br />

n<br />

2<br />

2<br />

SET 2:<br />

x(<br />

u,<br />

m,<br />

n)<br />

u m<br />

y(<br />

u,<br />

m,<br />

n)<br />

u m<br />

z(<br />

u,<br />

m,<br />

n)<br />

u m<br />

w(<br />

u,<br />

m,<br />

n)<br />

u m<br />

2<br />

2<br />

2<br />

2<br />

n<br />

n<br />

n<br />

2<br />

2<br />

2<br />

n<br />

2<br />

X ( m,<br />

n)<br />

2mn<br />

2.2Pattern 2:<br />

Equation (3) can be written as<br />

2 2 2<br />

p X v 1<br />

(6)<br />

Assume<br />

v<br />

2 2<br />

a b<br />

(7)<br />

Write 1 as<br />

2n<br />

2n<br />

(1 i)<br />

(1 i)<br />

1 (8)<br />

2n<br />

2<br />

Substituting (7) and (8) in (6) and using the method of factorization, define<br />

2n<br />

2 (1 i)<br />

p iX ( a ib)<br />

(9)<br />

n<br />

2<br />

Equating real and imaginary parts of (9),we have<br />

p ( a<br />

X ( a<br />

n<br />

n<br />

b )cos 2absin<br />

2 2<br />

2 2<br />

<br />

n<br />

n<br />

b )sin 2abcos<br />

2 2<br />

2 2<br />

<br />

www.<strong>ijcer</strong>online.com ||May ||2013|| Page 24

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