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Astronomy Principles and Practice Fourth Edition.pdf

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158 Geocentric planetary phenomena<br />

Proceeding in this way, it is, therefore, possible to construct an accurate model of the Solar System<br />

in terms of the distance of the Earth from the Sun without knowing the scale absolutely. Such a model<br />

was obtained in the 16th century. It was a far more difficult problem, only satisfactorily solved with<br />

the advent of radar, to measure the scale.<br />

12.8 Geocentric motion of a planet<br />

Once the sidereal period T of a planet is found, also the mean heliocentric distance a, the velocity V<br />

of the planet in its orbit (assumed circular) can be calculated. Thus,<br />

V = 2πa<br />

T .<br />

For two planets, therefore, the ratio of their orbital velocities is given by<br />

V 2<br />

V 1<br />

=<br />

(<br />

a2<br />

a 1<br />

)(<br />

T1<br />

T 2<br />

)<br />

(12.3)<br />

where the subscripts 1 <strong>and</strong> 2 refer to the inner <strong>and</strong> outer planet respectively. Putting in values, it is<br />

found that the velocity of the inner planet is greater than that of the outer.<br />

As we shall see later, Kepler found that for any planet,<br />

a 3 ∝ T 2<br />

or<br />

a 3 = kT 2 (12.4)<br />

where k is a constant.<br />

Then by equation (12.4),<br />

( ) 1/2<br />

a<br />

3<br />

T = .<br />

k<br />

According to Kepler, therefore, we may write for the two planets,<br />

T 1 =<br />

(<br />

a<br />

3<br />

1<br />

k<br />

) 1/2<br />

T 2 =<br />

(<br />

a<br />

3<br />

2<br />

k<br />

) 1/2<br />

.<br />

Substituting for T 1 <strong>and</strong> T 2 in equation (12.3), we obtain,<br />

( )<br />

V 1/2 2 a1<br />

= . (12.5)<br />

V 1 a 2<br />

In figure 12.8, the orbits of the Earth <strong>and</strong> a planet are shown, the radii of the orbits (assumed<br />

circular <strong>and</strong> coplanar) being a <strong>and</strong> b units respectively. Since the planet is a superior one, b is greater<br />

than a.<br />

At opposition, the positions of the planet <strong>and</strong> Earth are P 1 <strong>and</strong> E 1 <strong>and</strong> their velocity vectors are<br />

shown as V P <strong>and</strong> V ⊕ respectively, tangential to their orbits.<br />

Now by equation (12.5), V P < V ⊕ <strong>and</strong> so the angular velocity of the planet as observed from the<br />

Earth is<br />

V P − V ⊕<br />

P 1 E 1<br />

<strong>and</strong> is in a direction opposite to the orbital movement. It is, therefore, retrograde at opposition.

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