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Astronomy Principles and Practice Fourth Edition.pdf

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The telescope <strong>and</strong> the collected energy 243<br />

Figure 16.3. The relationship between the brightness of an extended object <strong>and</strong> the brightness of its image.<br />

solid angle of the source per unit time. A convenient measure of the brightness might be expressed in<br />

power units as J m −2 sr −1 s −1 or W m −2 sr −1 . Suppose that an extended source of brightness, B 1 ,at<br />

a distance, d 1 , from an optical system of collecting area, A, presents an elemental area, σ 1 ,<strong>and</strong>that<br />

an image of this is formed (see figure 16.3). The amount of energy collected by the system per unit of<br />

time, or the flux collected by the aperture is given by<br />

( )<br />

A<br />

1 = B 1 σ 1<br />

d1<br />

2 (16.7)<br />

where the bracketed term corresponds to the solid angle associated with the flux accepted by the<br />

aperture. The ratio of d 2 to d 1 sets the magnification of the system <strong>and</strong> the corresponding area of<br />

the image is given by<br />

( )<br />

d<br />

2<br />

σ 2 = σ 2 1<br />

d1<br />

2 . (16.8)<br />

Now for this same optical system, we can also consider the case with the radiation originating at<br />

the position of the first image from a source of brightness B 2 , providing an elemental area σ 2 , with the<br />

drawn ray paths following the opposite direction to the original situation. The flux now entering the<br />

aperture is now<br />

( )<br />

A<br />

2 = B 2 σ 2<br />

d2<br />

2 . (16.9)<br />

If the fluxes for the two scenarios are set equal, then by equations (16.7) <strong>and</strong> (16.9),<br />

)<br />

)<br />

B 2 σ 2<br />

(<br />

A<br />

d 2 2<br />

= B 1 σ 1<br />

(<br />

A<br />

d 2 1<br />

so that<br />

( ) ( )<br />

σ1 d2<br />

2 B 2 = B 1<br />

σ 2 d1<br />

2 .<br />

By using equation (16.8),<br />

( )( )<br />

σ1 σ2<br />

B 2 = B 1<br />

σ 2 σ 1<br />

with the result that<br />

B 2 = B 1 .<br />

The brightness of an image of an extended object, therefore, matches that of the object. A<br />

telescope does not increase the brightness of an extended object—a fact not always appreciated. In<br />

fact, because of transmission losses in the optics, the brightness of any image of an extended source

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