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Astronomy Principles and Practice Fourth Edition.pdf

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Comparison of refractors <strong>and</strong> reflectors 269<br />

Figure 16.32. Example 16.2—circle of least confusion of a chromatic change.<br />

size increases. The mechanical strains, due to the collector’s own weight, will vary according to the<br />

point in the sky to which the telescope is directed; for large telescopes the strains are sufficient to<br />

distort the optical surfaces <strong>and</strong> spoil the images. Very little can be done in the case of the refractor as<br />

the objective can be supported only by its rim. However, in the case of a reflector, the collector can be<br />

supported over all of the rear surface. In fact, it is possible to design a system of pressure pads in the<br />

support to relieve the strain in the mirror, according to its position.<br />

From the point of view of light-gathering power, it is not profitable to construct large refractors.<br />

As the diameter of the objective increases, so does its thickness <strong>and</strong> the amount of absorption. The ratio<br />

of the transmission to the diameter decreases as the telescope aperture increases <strong>and</strong>, thus, the law of<br />

diminishing returns applies. For reflectors with the same focal ratio but ranging in size, the fractional<br />

loss in transmission efficiency is constant. Other properties of telescope systems are discussed later in<br />

their relevant sections. Those which can be compared have been summarized in table 16.1.<br />

Example 16.2. A 400 cm diameter lens has focal lengths in the blue <strong>and</strong> red regions of the spectrum<br />

given by: F B = 2995 mm, F R = 3000 mm.<br />

(i) What is the value of the focal length corresponding to the position of the circle of least<br />

confusion<br />

(ii) What is the linear size of the image of a star at its focal position<br />

(i) By similar triangles (see figure 16.32):<br />

D<br />

F B<br />

=<br />

d<br />

F c − F B<br />

<strong>and</strong><br />

D<br />

F R<br />

=<br />

d<br />

F R − F c<br />

.<br />

Dividing these identities,<br />

giving<br />

Inserting the values gives<br />

F R<br />

F B<br />

= F R − F c<br />

F c − F B<br />

F c =<br />

2F B F R<br />

F R + F B<br />

.<br />

2 × 3000 × 2995<br />

F c =<br />

5995<br />

F c = 2997 mm.

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