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Astronomy Principles and Practice Fourth Edition.pdf

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The relationship between mean solar time <strong>and</strong> sidereal time 95<br />

For navigational purposes based on solar positional measurements, it is, therefore, accurate enough to<br />

rewrite equation (9.7) as<br />

Ephemeris transit = 12 h − (9.9)<br />

since the equation of time is a slowly varying quantity <strong>and</strong> T is only of the order of 66 seconds at<br />

present (2000).<br />

Hence, by equation (9.6),<br />

GHA⊙ = GHAMS + 12 h − Ephemeris transit. (9.10)<br />

9.4 The relationship between mean solar time <strong>and</strong> sidereal time<br />

We have seen that the mean solar day is about 4 minutes longer than the sidereal day. A more precise<br />

relationship will now be developed.<br />

Equation (9.4) gives<br />

LST = HAMS + RAMS. (9.11)<br />

Let the values of these quantities be T 1 , H 1 <strong>and</strong> R 1 at a particular epoch <strong>and</strong> T 2 , H 2 <strong>and</strong> R 2 one<br />

mean solar day later.<br />

Then by equation (9.11), we have<br />

Subtracting, we obtain<br />

T 1 = H 1 + R 1<br />

T 2 = H 2 + R 2 .<br />

But H 2 − H 1 = 24 h , since 1 mean solar day has elapsed.<br />

The Sun’s mean angular rate is n, where<br />

T 2 − T 1 = (H 2 − H 1 ) + (R 2 − R 1 ). (9.12)<br />

n = 360 ◦ /365 1 4 days<br />

or<br />

n = 24 h /365 1 4 days<br />

so that the increase in the mean sun’s right ascension in 1 mean solar day is 24 h /365 1 4<br />

. This must be<br />

the quantity (R 2 − R 1 ). Hence, equation (9.12) becomes<br />

T 2 − T 1 = 24 h + 24 h /365 1 4<br />

= 24 h (1 + 1/365 1 4 )<br />

= 24 h (366 1 4 /365 1 4<br />

) of sidereal time.<br />

This interval of sidereal time is equal to 24 hours of mean solar time so that we obtain the relation:<br />

Alternatively,<br />

24 h mean solar time = 24 h × 366 1 4<br />

365 1 4<br />

24 h sidereal time = 24 h × 365 1 4<br />

366 1 4<br />

sidereal time.<br />

mean solar time.

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