Astronomy Principles and Practice Fourth Edition.pdf

Answers to problems 467
9. 5000 Å
10. Lα = 1215 Å—which is in the deep ultraviolet, well absorbed by the Earth’s atmosphere
11. 1·0574 × 10 8 T
12. −42 km s −1
13. 0·17 Å
Chapter 16
1. 43·6mm
2. 34·4arcsecmm −1 , 0.058 mm
3. Assuming that the 36 mm length is used → 137·5mm
4. 1·9mm
5. 2·91 × 10 −2 mm
6. ≈3 × 10 7 s −1 (Assume λ = 550 nm)
7. 28·6s −1 ;37·8:1
8. 5090 mm (Hint: Use lens-makers formula)
9. (i) 8000 mm (ii) f/16 (iii) −533 mm (iv) 1/25
(Hint: Draw diagram and apply similar triangles)
10. 0·53%
11. 1·15%
12. 0·15 arc sec
Chapter 17
1. 150, Yes, m > D/8
2. D = 6·7 m
3. 1·34 × 10 −6 rad; 1·34 × 10 −2 mm (Airy disc = 2α × F)
4. Aberrated image size = 0·0025 (Hint: See example 16.2), Airy disc = 0·0013
5. Aberrated image size = 0·0015 (Hint: See example 16.3), Airy disc = 0·0016
6. 630 mm; 16·m2
7. 208 mm
8. τ = 17/10; Feb 1st 1575 (assuming no losses)
9. 13·4arcsec
Chapter 18
1. (i) 13·9 (ii) 14·2 (both assuming no losses)
2. 100 s
3. 16·m3
4. ≈ 10 2
5. 0·26%
Chapter 19
1. 8·24
2. 4·9
3. 8·2, 86%
4. 22 ◦ 36 ′