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Astronomy Principles and Practice Fourth Edition.pdf

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Transformation of one coordinate system into another 69<br />

Figure 8.9. The conversion of azimuth <strong>and</strong> altitude to hour angle <strong>and</strong> declination.<br />

The required celestial sphere is shown in figure 8.9 where X is the body’s position.<br />

In spherical triangle PZX, we see that we require to find arc PX <strong>and</strong> angle ZPX. We calculate<br />

PX first of all, using the cosine formula because we know two sides PZ, ZX <strong>and</strong> the included angle<br />

PZX.<br />

Hence, we may write,<br />

cos PX = cos PZ cos ZX + sin PZ sin ZXcos PZX<br />

or<br />

sin δ = sin φ sin a + cos φ cos a cos A.<br />

This equation enables δ to be calculated.<br />

A second application of the cosine formula gives<br />

or<br />

cos ZX = cos PZ cos PX + sin PZ sin PX cos ZPX<br />

sin a = sin φ sin δ + cos φ cos δ cos H.<br />

Re-arranging, we obtain<br />

sin a − sin φ sin δ<br />

cos H =<br />

cos φ cos δ<br />

giving H ,sinceδ is now known.<br />

Alternatively, using the four-parts formula with ZX, PZX, PZ <strong>and</strong> ZPX, we obtain<br />

or<br />

cos PZ cos PZX = sin PZ cot ZX − sin PZX cot ZPX<br />

sin φ cos A = cos φ tan a + sin A cot H<br />

giving<br />

sin A<br />

tan H =<br />

sin φ cos A − cos φ tan a .<br />

We consider the problem in reverse by means of a numerical example.

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