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Astronomy Principles and Practice Fourth Edition.pdf

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98 The celestial sphere: timekeeping systems<br />

Figure 9.6. The Greenwich date <strong>and</strong> zone time.<br />

sailors when they arrived home one day too late by their reckoning, <strong>and</strong> which enabled Jules Verne’s<br />

character Phileas Fogg to win his wager to journey round the World in 80 days.<br />

In many problems it is necessary to convert from a particular zone time <strong>and</strong> date to the<br />

corresponding GMT <strong>and</strong> date. The Greenwich Date isthenamegiventoaGMTplusthedateat<br />

Greenwich <strong>and</strong> we now consider the relationship between a Greenwich Date <strong>and</strong> a zone time <strong>and</strong> date.<br />

9.6 The Greenwich date <strong>and</strong> zone time (with date)<br />

In figure 9.6 the Earth is seen as viewed from above the North Pole P, the meridian of longitude PGA<br />

through Greenwich G meeting the equator in A. The International Date Line PL cuts the equator at<br />

L, its southern half being, of course, unseen.<br />

The st<strong>and</strong>ard meridian PB, of longitude λ ◦ E, likewise meets the equator at B, whereAPB =<br />

λ ◦ E.<br />

Let a civil day, for example November 3rd, begin at the Date Line. It does so when the HAMS is<br />

12 h for that meridian, i.e. the mean sun is at M 1 , above the point A on the equator.<br />

November 3rd will not begin for places in the zone keeping the zone time of the st<strong>and</strong>ard meridian<br />

PB until the mean sun has moved round the celestial sphere to be at M 2 , above D, whereD is 180 ◦<br />

distant from B round the equator.<br />

For the Greenwich meridian <strong>and</strong> Zone 0, November 3rd will begin even later, when the mean sun<br />

has revolved until it is above L, atM 3 .<br />

The Greenwich Date is then November 3rd, GMT 00 h 00.<br />

But the zone time with date at B is by then November 3rd, ZTλ h ,sinceDPL = APB = λ E.<br />

The required relation is thus<br />

GMT = ZT − λE<br />

where λ is now expressed in hours.<br />

By taking a western st<strong>and</strong>ard meridian at F, say,whereAPF = λW, it is easily shown that the<br />

relation is given by<br />

GMT = ZT + λW<br />

λ being expressed in hours.<br />

We may, therefore, combine these rules by adopting as before the convention that a western<br />

longitude is positive <strong>and</strong> an eastern one is negative. Thus,<br />

GMT = ZT + λ. (9.15)

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