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Bush__The_Essential_Physics_for_Medical_Imaging - Biomedical ...

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<strong>The</strong>re<strong>for</strong>e, the ourpur exposure increases by approximately 78% (Fig. 5-36).An increase in k Vp increases the efficiency of x-ray production and the quantity andquality of the x-ray beam.Changes in the kVp must be compensated by corresponding changes in mAsto maintain the same exposure. At 80 kVp, 1.78 units of exposure occur <strong>for</strong> every1 unit of exposure at 60 kVp. To achieve the original 1 unit of exposure, the mAsmust be adjusted to 1/1.78 = 0.56 times the original mAs, which is a reduction of44%. An additional consideration of technique adjustment concerns the x-rayattenuation characteristics of the patient. To achieve equal transmitted exposurethrough a typical patient (e.g., 20 cm tissue), the mAs varies with the fifth powerof the kVp ratio:( kV Pl)5 X mAs l = mAszkVpzAccording to Equation 5-8, if a 60-kVp exposure requires 40 mAs <strong>for</strong> aproper exposure through a typical adult patient, at 80 kVp the proper mAs isapproximately( 60)5 80 X 40 mAs == 9.5 mAsor abour one fourth of the original mAs. <strong>The</strong> value of the exponent (betweenfour and five) depends on the thickness and attenuation characteristics of thepatient.3. <strong>The</strong> tube current (mA) is equal to the number of electrons flowing from thecathode to the anode per unit time. <strong>The</strong> exposure of the beam <strong>for</strong> a given kVpand filtration is proportional to the tube current.4. <strong>The</strong> exposure time is the duration of x-ray production. <strong>The</strong> quantity of x-raysis directly proportional to the product of tube current and exposure time(mAs).5. <strong>The</strong> beam filtration modifies the quantity and quality of the x-ray beam by selectivelyremoving the low-energy photons in the spectrum. This reduces the pho-X-ray output spectrum(Equal tube current)Q)(.)100000c 80000Q)::JG=C00.t::a.Q)>6000040000~ 20000 .Q)0:::0040 60 80Energy (keV)FIGURE 5-36. X-ray tubeoutput intensity variesstrongly with tube voltage(kVp). In this example, thesame tube current and exposuretimes (mAs) are compared<strong>for</strong> 60 to 120 kVp. <strong>The</strong>relative area under eachspectrum roughly follows asquared dependence (characteristicradiation is ignored).

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