18.02.2016 Views

Understanding API ICP653 Reading 7-Worksheet-04 Part1

Understanding API ICP653 Reading 7-Worksheet-04 Part1

Understanding API ICP653 Reading 7-Worksheet-04 Part1

SHOW MORE
SHOW LESS

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

EXAMPLE: A tank 38 feet tall, 150 feet diameter, displays a large area of<br />

corrosion. The corroded area measures approximately 23 inches wide and 21<br />

inches in height. The inspector has determined the least thickness in the area<br />

of corrosion to be 3/16 or .187 inches. Calculate the "L" length.<br />

ANSWER: L = 3.7√Dt 2<br />

L = 3.7 √(150 X .187)<br />

L = 3.7 √28.05<br />

L = 3.7 X 5.30<br />

L = 19.61 inches or 19 5/8 inches approx.<br />

Note:<br />

“The corroded area measures approximately 23 inches wide and 21 inches in<br />

height.” does not have any impact on the calculation!<br />

Charlie Chong/ Fion Zhang

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!