6 folier pr. side - NTNU
6 folier pr. side - NTNU
6 folier pr. side - NTNU
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<strong>NTNU</strong><br />
<strong>NTNU</strong><br />
<strong>NTNU</strong><br />
Slide 361<br />
Slide 363<br />
Transformasjon for 3-fase viklinger<br />
■ For trefase viklingen finner man :<br />
I s =<br />
[ ] [ ]<br />
[ ] T k<br />
2 s<br />
s<br />
s<br />
S<br />
T<br />
⋅ Isa<br />
⋅ a + Isb<br />
⋅ b + Isc<br />
⋅ c Is<br />
= I sa I sb Isc<br />
3<br />
k k k k k k<br />
k k k<br />
I ⋅ α + I ⋅β<br />
+ I ⋅ γ<br />
I s = I I I<br />
I s = sα<br />
sβ<br />
sγ<br />
k<br />
α =<br />
2<br />
3<br />
k 2<br />
β = −<br />
3<br />
k<br />
γ =<br />
1<br />
3<br />
⎡cos<br />
θ k ⎤<br />
k<br />
α =<br />
⎢ ⎥<br />
⎢<br />
sin θ k ⎥<br />
⎢⎣<br />
0 ⎥⎦<br />
sα<br />
sβ<br />
sγ<br />
S<br />
0 S<br />
0 S<br />
[ cos θk<br />
⋅ a + cos( θk<br />
− 120 ) ⋅ b + cos( θk<br />
− 240 ) ⋅ c ]<br />
S<br />
0 S<br />
0 S<br />
[ sin θ k ⋅ a + sin( θ k − 120 ) ⋅ b + sin( θk<br />
− 240 ) ⋅ c ]<br />
S S S<br />
[ a + b + c ]<br />
⎡−<br />
sin θk<br />
⎤<br />
k<br />
β =<br />
⎢ ⎥<br />
⎢<br />
cos θk<br />
⎥<br />
⎢⎣<br />
0 ⎥⎦<br />
⎡0⎤<br />
k<br />
γ =<br />
⎢ ⎥<br />
⎢<br />
0<br />
⎥<br />
⎢⎣<br />
1⎥⎦<br />
Trondheim 2000<br />
Transformasjon for 3-fase rotor viklinger<br />
i en asynkronmaskin<br />
■ Finner da Park-transformasjonen:<br />
0<br />
0<br />
⎡ cosθ<br />
⎤<br />
r cos( θr<br />
−120<br />
) cos( θr<br />
− 240 )<br />
k 2 ⎢<br />
0<br />
0 ⎥<br />
�rr<br />
= ⋅ ⎢−<br />
sin θr<br />
− sin( θr<br />
−120<br />
) − sin( θr<br />
− 240 )<br />
3<br />
⎥<br />
⎢<br />
⎥<br />
⎣<br />
1/<br />
2 1/<br />
2<br />
1/<br />
2<br />
⎦<br />
■ Den inverse Park-transformasjonen:<br />
⎡ cos θr<br />
− sin θr<br />
1⎤<br />
−k<br />
⎢<br />
0<br />
0<br />
�<br />
⎥<br />
rr =<br />
⎢<br />
cos( θr<br />
−120<br />
) − sin( θr<br />
−120<br />
) 1<br />
⎥<br />
0<br />
0<br />
⎢⎣<br />
cos( θ − 240 ) − sin( θ − 240 ) 1⎥<br />
r<br />
r ⎦<br />
k<br />
−k<br />
k ⎡�<br />
⎤<br />
⎡ ⎤<br />
ss �<br />
−k<br />
�ss<br />
�<br />
� = ⎢ ⎥<br />
� =<br />
k<br />
⎢<br />
−k<br />
⎥<br />
⎣ � �rr<br />
⎦<br />
⎣ � �rr<br />
⎦<br />
Slide 365<br />
Elektriske likninger og momentbalanse i<br />
den transformerte modell……….<br />
■ Transformerte modell:<br />
k<br />
−k<br />
k k k dΨ<br />
k d�<br />
k<br />
k k SR −k<br />
U = � I + + � Ψ<br />
� = � � �<br />
dt dt<br />
k k SR k SR −k<br />
k k k<br />
k k SR −k<br />
Ψ = � Ψ = � � � I = � I � = � � �<br />
■ Motstander og induktansmatrise:<br />
⎡R<br />
s 0 0 0 0 0 ⎤<br />
⎢<br />
⎥<br />
⎢<br />
0 R s 0 0 0 0<br />
⎥<br />
⎢ 0 0 R<br />
⎥<br />
s 0 0 0<br />
k<br />
� = ⎢<br />
⎥<br />
⎢ 0 0 0 R r 0 0 ⎥<br />
⎢ 0 0 0 0 R ⎥<br />
r 0<br />
⎢<br />
⎥<br />
⎢⎣<br />
0 0 0 0 0 R r ⎥⎦<br />
Trondheim 2000<br />
⎡3<br />
3<br />
⎤<br />
⎢ ⋅ L sh + Lsσ<br />
0 0 ⋅ L h 0 0<br />
2<br />
2<br />
⎥<br />
⎢<br />
3<br />
3<br />
⎥<br />
⎢ 0 ⋅ L<br />
⎥<br />
sh + Lsσ<br />
0 0<br />
⋅ L h 0<br />
⎢<br />
2<br />
2<br />
⎥<br />
k<br />
=<br />
⎢ 0<br />
0 Lsσ<br />
0<br />
0 0 ⎥<br />
�<br />
⎢ 3<br />
3<br />
⎥<br />
⎢ ⋅ L h 0 0 ⋅ Lrh<br />
+ L rσ<br />
0 0 ⎥<br />
⎢ 2<br />
2<br />
⎥<br />
⎢<br />
3<br />
3<br />
0<br />
⋅ L<br />
⋅ + ⎥<br />
h 0 0 Lrh<br />
Lrσ<br />
0<br />
⎢<br />
2<br />
2<br />
⎥<br />
⎢⎣<br />
0<br />
0 0 0<br />
0 L rσ<br />
⎥⎦<br />
Trondheim 2000<br />
<strong>NTNU</strong><br />
<strong>NTNU</strong><br />
<strong>NTNU</strong><br />
Slide 362<br />
Slide 364<br />
Transformasjon for 3-fase viklinger<br />
■ Finner da Park-transformasjonen:<br />
⎡ cos θk<br />
k ⎢<br />
�ss<br />
= ⋅ ⎢−<br />
sin θ<br />
3<br />
⎢<br />
⎣<br />
1/<br />
2<br />
0<br />
0<br />
cos( θ<br />
⎤<br />
k −120<br />
) cos( θ k − 240 )<br />
0<br />
⎥<br />
− sin( θk<br />
−120<br />
) − sin( θk<br />
− 240 ) ⎥<br />
1/<br />
2<br />
1/<br />
2 ⎥<br />
⎦<br />
2 0<br />
k<br />
■ Den inverse Park-transformasjonen:<br />
⎡ cos θk<br />
− sin θ k 1⎤<br />
−k<br />
⎢<br />
0<br />
0<br />
�<br />
⎥<br />
ss =<br />
⎢<br />
cos( θk<br />
−120<br />
) − sin( θk<br />
−120<br />
) 1<br />
⎥<br />
0<br />
0<br />
⎢⎣<br />
cos( θ − 240 ) − sin( θ − 240 ) 1⎥<br />
k<br />
k ⎦<br />
Elektriske likninger og momentbalanse i<br />
den transformerte modell<br />
■ Fysikalsk modell:<br />
SR<br />
SR SR SR dΨ<br />
SR SR SR<br />
U � I +<br />
Ψ = � I<br />
dt<br />
■ Utledning av transformerte modell:<br />
SR<br />
T ∂<br />
∂θ<br />
Trondheim 2000<br />
SR<br />
SR<br />
= M e = ⋅ ( I ) ⋅ ⋅ I<br />
SR<br />
k k SR k SR SR k dΨ<br />
k k SR k SR SR<br />
U = � U = � � I + �<br />
Ψ = � Ψ = � � I<br />
dt<br />
k k SR<br />
I = � I<br />
SR −k k<br />
k k SR<br />
SR −k<br />
k<br />
I = � I Ψ = � Ψ Ψ = � Ψ<br />
−k<br />
k ( � Ψ )<br />
k k SR k SR −k<br />
k k d<br />
U = � U = � � � I + �<br />
dt<br />
k<br />
−k<br />
k k SR −k<br />
k k −k<br />
dΨ<br />
k d�<br />
k<br />
U = � � � I + � � + � Ψ<br />
dt dt<br />
Slide 366<br />
p<br />
2<br />
k<br />
−k<br />
k k k dΨ<br />
k d�<br />
k<br />
U = � I + + � Ψ<br />
dt dt<br />
k k SR −k<br />
� = � � �<br />
Elektriske likninger og momentbalanse i<br />
den transformerte modell……….<br />
■ Følgende viklinger er<br />
magnetisk koblet:<br />
➨ Stator- og rotor α-akse<br />
viklinger<br />
➨ Stator- og rotor β-akse<br />
viklinger<br />
➨ γ-systemets induktans er<br />
ikke koblet med noen av<br />
de andre viklingene<br />
α k<br />
Θ k<br />
a r<br />
+ usα i -<br />
sα<br />
θ<br />
-<br />
+<br />
urα-<br />
a S<br />
+ - u ra<br />
+<br />
usa -<br />
�<br />
Trondheim 2000<br />
b S c S<br />
-<br />
usβ -<br />
urβ +<br />
+<br />
isβ β k<br />
Trondheim 2000