C H A P T E R 5 Analytic Trigonometry
C H A P T E R 5 Analytic Trigonometry
C H A P T E R 5 Analytic Trigonometry
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524 Chapter 5 <strong>Analytic</strong> <strong>Trigonometry</strong><br />
114.<br />
115. The graph of y1 is a vertical shift of the graph of y2 one unit upward so y1 y2 1.<br />
117.<br />
S 6hs <br />
where h 2.4 inches, s 0.75 inch, and is the given angle.<br />
3<br />
s 2<br />
3 cos <br />
2 sin , 0 < ≤ 90<br />
(a) For a surface area of 12 square inches,<br />
S 62.40.75 3 3 cos <br />
0.752 2 sin <br />
3 cos <br />
10.8 0.84375 12<br />
sin <br />
3 cos <br />
0.84375 sin 1.2.<br />
y x 3 4 cos x<br />
Zeros: x 1.8431, 2.1758,<br />
3.9903, 8.8935, 9.8820<br />
11<br />
−4 20<br />
Problem Solving for Chapter 5<br />
1. (a) Since<br />
Using the solve function of a graphing calculator gives<br />
49.91479 or 59.86118.<br />
cos ±1 sin 2 <br />
tan <br />
sin <br />
±<br />
cos <br />
cot 1<br />
tan ± 1 sin2 <br />
sin <br />
sec 1<br />
±<br />
cos <br />
cos 1<br />
sin <br />
—CONTINUED—<br />
sin <br />
1 sin 2 <br />
1<br />
1 sin 2 <br />
−2<br />
<br />
<br />
<br />
12<br />
(b) Using a graphing calculator yields the following graph:<br />
cos 3x<br />
116. y1 <br />
cos x<br />
If the graph of y2 is reflected in the x-axis and then<br />
shifted upward by one unit, it coincides with the<br />
graph of y1 . Therefore,<br />
, y2 2 sin x2 cos 3x<br />
cos x 2 sin x2 1.<br />
So, y 1 1 y 2 .<br />
118. y 2 <br />
Approximate roots:<br />
3.1395, 2.0000,<br />
1<br />
2 x2 3 sin<br />
2<br />
0.4378, 2.0000<br />
y 2 1<br />
2 x2 3 sin<br />
sin 2 cos 2 1 and cos 2 1 sin 2 : We also have the following relationships:<br />
20<br />
0<br />
0<br />
(0.9553, 11.99)<br />
cos sin <br />
2<br />
sin <br />
tan <br />
sin <br />
2<br />
sin<br />
cot <br />
<br />
2<br />
sin <br />
1<br />
sec <br />
sin <br />
2<br />
csc 1<br />
sin <br />
3<br />
4<br />
Using the minimum function yields<br />
0.9553 radians or 54.73466.<br />
x<br />
x<br />
2<br />
−10 10<br />
7<br />
−7