13.02.2014 Views

Chapter 7 Rational Functions - College of the Redwoods

Chapter 7 Rational Functions - College of the Redwoods

Chapter 7 Rational Functions - College of the Redwoods

SHOW MORE
SHOW LESS

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

Section 7.8 Applications <strong>of</strong> <strong>Rational</strong> <strong>Functions</strong> 737<br />

Solving d = vt for <strong>the</strong> time t,<br />

d (mi) v (mi/h) t (h)<br />

Upstream 150 32 − c ?<br />

Downstream 150 32 + c ?<br />

Table 3. Entering <strong>the</strong> given data in a distance,<br />

speed, and time table.<br />

t = d v .<br />

In <strong>the</strong> first row <strong>of</strong> Table 3, we have d = 150 miles and v = 32 − c miles per hour.<br />

Hence, <strong>the</strong> time it takes <strong>the</strong> boat to go upstream is given by<br />

t = d v = 150<br />

32 − c .<br />

Similarly, upon examining <strong>the</strong> data in <strong>the</strong> second row <strong>of</strong> Table 3, <strong>the</strong> time it takes <strong>the</strong><br />

boat to return downstream to its starting location is<br />

These results are entered in Table 4.<br />

t = d v = 150<br />

32 + c .<br />

d (mi) v (mi/h) t (h)<br />

Upstream 150 32 − c 150/(32 − c)<br />

Downstream 150 32 + c 150/(32 + c)<br />

Table 4. Calculating <strong>the</strong> time<br />

to go upstream and return.<br />

Because <strong>the</strong> total time to go upstream and return is 10 hours, we can write<br />

150<br />

32 − c + 150<br />

32 + c = 10.<br />

Multiply both sides by <strong>the</strong> common denominator (32 − c)(32 + c).<br />

( 150<br />

(32 − c)(32 + c)<br />

32 − c + 150 )<br />

= 10(32 − c)(32 + c)<br />

32 + c<br />

150(32 + c) + 150(32 − c) = 10(1024 − c 2 )<br />

We can make <strong>the</strong> numbers a bit smaller by noting that both sides <strong>of</strong> <strong>the</strong> last equation<br />

are divisible by 10.<br />

15(32 + c) + 15(32 − c) = 1024 − c 2<br />

Expand, simplify, make one side zero, <strong>the</strong>n factor.<br />

Version: Fall 2007

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!