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Chapter 7 Rational Functions - College of the Redwoods

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Section 7.4 Products and Quotients <strong>of</strong> <strong>Rational</strong> <strong>Functions</strong> 661<br />

7.4 Products and Quotients <strong>of</strong> <strong>Rational</strong> <strong>Functions</strong><br />

In this section we deal with products and quotients <strong>of</strong> rational expressions. Before we<br />

begin, we’ll need to establish some fundamental definitions and technique. We begin<br />

with <strong>the</strong> definition <strong>of</strong> <strong>the</strong> product <strong>of</strong> two rational numbers.<br />

Definition 1. Let a/b and c/d be rational numbers. The product <strong>of</strong> <strong>the</strong>se<br />

rational numbers is defined by<br />

a<br />

b × c d = a × c<br />

b × d , or more compactly, a<br />

b · c<br />

d = ac<br />

bd . (2)<br />

The definition simply states that you should multiply <strong>the</strong> numerators <strong>of</strong> each rational<br />

number to obtain <strong>the</strong> numerator <strong>of</strong> <strong>the</strong> product, and you also multiply <strong>the</strong><br />

denominators <strong>of</strong> each rational number to obtain <strong>the</strong> denominator <strong>of</strong> <strong>the</strong> product. For<br />

example,<br />

2<br />

3 · 5<br />

7 = 2 · 5<br />

3 · 7 = 10<br />

21 .<br />

Of course, you should also check to make sure your final answer is reduced to lowest<br />

terms.<br />

Let’s look at an example.<br />

◮ Example 3.<br />

Simplify <strong>the</strong> product <strong>of</strong> rational numbers<br />

6<br />

231 · 35<br />

10 . (4)<br />

First, multiply numerators and denominators toge<strong>the</strong>r as follows.<br />

6<br />

231 · 35<br />

10 = 6 · 35<br />

231 · 10 = 210<br />

2310 .<br />

However, <strong>the</strong> answer is not reduced to lowest terms. We can express <strong>the</strong> numerator as<br />

a product <strong>of</strong> primes.<br />

210 = 21 · 10 = 3 · 7 · 2 · 5 = 2 · 3 · 5 · 7<br />

It’s not necessary to arrange <strong>the</strong> factors in ascending order, but every little bit helps.<br />

The denominator can also be expressed as a product <strong>of</strong> primes.<br />

2310 = 10 · 231 = 2 · 5 · 7 · 33 = 2 · 3 · 5 · 7 · 11<br />

We can now cancel common factors.<br />

210<br />

2310 = 2 · 3 · 5 · 7<br />

2 · 3 · 5 · 7 · 11 = 2 · 3 · 5 · 7<br />

2 · 3 · 5 · 7 · 11 = 1 11<br />

(5)<br />

11<br />

Copyrighted material. See: http://msenux.redwoods.edu/IntAlgText/<br />

Version: Fall 2007

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