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Equation (6) can be improved by considering how the pressure drop coefficients f ci<br />

actually<br />

depend on the Reynolds number. In our case, owing to the turbulent flow condition into the (core and<br />

heat exchangers) smooth channels, the following Blausius correlation [14] can be used:<br />

−0.25<br />

= 0.32<br />

e<br />

f c<br />

R<br />

were<br />

e<br />

≡<br />

REYNOLDS NUMBER<br />

=<br />

D e<br />

ρ v<br />

µ<br />

=<br />

Q<br />

m<br />

D e<br />

S µ<br />

e<br />

(8)<br />

and µ is the fluid viscosity, S e<br />

is the equivalent flow area of the considered channel or component and<br />

D e<br />

is the corresponding equivalent diameter.<br />

By considering the (8) Blausius correlation, the equation (6) becomes:<br />

1.75<br />

m<br />

Q<br />

∆P<br />

∝<br />

ρ<br />

= ρ<br />

0.75<br />

v<br />

1.75<br />

µ<br />

0.25<br />

(9)<br />

The improved model (9), besides the hypothesis (7), needs only the following further<br />

approximation:<br />

0.25<br />

µ i<br />

0.25<br />

µ<br />

≈ 1<br />

2.2 Gravitational pull and energy balance in steady conditions<br />

In steady state convection, the kinetics energy dissipated by pressure drop is compensated by the<br />

work made by the gravity field along the entire loop. By considering unit volumes, we can write this<br />

balance in terms of pressure drops:<br />

∆P g<br />

= ∆P<br />

where the gravitational pull ∆P g<br />

is defined as:<br />

∆<br />

P g<br />

≡<br />

∫<br />

r r<br />

ρ g • d s<br />

(10)<br />

512

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