Lecture Notes for Computer Architecture II - St. Cloud State University

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3rd step Rem = Rem – Divisor ( this time divisor is larger so result is negative) Rem < 0 (1) Shift Q left, Q 0 = 0 (2) Restore Remainder (3) Shift Divisor Right Page | 98 0000 0100 Q ALU 0000 0000 0111 4th step Rem = Rem – Divisor Now Rem > 0 (1) Shift Q left, Q 0 = 1 (2) Shift Divisor Right 0000 0010 Q ALU 0001 0000 0011
5th step Rem = Rem – Divisor Now Rem > 0 (1) Shift Q left, Q 0 = 1 (2) Shift Divisor Right Page | 99 0000 0001 Q ALU 0011 0000 0001 4-bit divisor needs 5 iterations 8-bit divisor needs 9 iterations 32-bit divisor needs 33 iterations
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Page | 1 Lecture Notes for Computer
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knowledge given in the book chapter
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CS 320 SCHEDULE (tentative) Week Wh
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6. Project reports - Presentation C
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9. Course policies: 1) Satisfactory
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Size - keep shrinking 1994 124mm 2
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Families of different models - Inte
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Super Computers CRAY - 1 st vector
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Fastest super computers November 20
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Class Activity - 2. Trace the conte
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TUTOR 1.32:> PHYSICAL ADDRESS=00002
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Class Activity 3 - Study of instruc
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Class Activity 4 - Study of instruc
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Performance Improvement at Instruct
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5. Register indirect addressing mod
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High Level Language Statements Ass
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Lecture 7 Data transfer memory reg
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Problem Translate HLL statement A[
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More MIPS instructions jump j jr $S
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Problem Translate the following Whi
Page 47 and 48: Problem Translate the following exp
Page 49 and 50: Problem Translate the following exp
Page 51 and 52: Lecture 10 Translation of High Leve
Page 53 and 54: Translation of Procedures Problem H
Page 55 and 56: Example Write the MIPS code to comp
Page 57 and 58: Program Counter -relative op rs rt
Page 59 and 60: Example Opcode always 1 byte Memory
Page 61 and 62: Lecture 13 Enhancing Performance at
Page 63 and 64: Number Systems Numbers + ve numbers
Page 65 and 66: Example: Design a one bit ALU with
Page 67 and 68: Lecture 14 - Performance Improvemen
Page 69 and 70: Design of Adders c 1 a n , ..., a 1
Page 71 and 72: Carry lookahead adder Problem with
Page 73 and 74: Another look at CLA xi + yi = Pi xi
Page 75 and 76: 4-bit CLA Page | 75 generates C3 ge
Page 77 and 78: Lecture 15 Performance Improvement
Page 79 and 80: Example 981 X 1234 0981 X 1234 mult
Page 81 and 82: Example Consider the multiplication
Page 83 and 84: 2 nd version Reduce cost by reducin
Page 85 and 86: 4th step 4 bits registers 0010 4 bi
Page 87 and 88: 0010 ADDER Page | 87 0001 0010 ADDE
Page 89 and 90: 2's complement of m'cand 1111110101
Page 91 and 92: 0010 ADDER Page | 91 1111 0001 1 no
Page 93 and 94: Lecture 16 - Performance Improvemen
Page 95 and 96: Hardware units needed to perform th
Page 97: Step 1 Rem = Rem - Divisor ( this t
Page 101 and 102: 2nd step Shift remainder left Rem =
Page 103 and 104: 3 rd version of Division algorithm
Page 105 and 106: Step 3 Rem = Rem - Div Rem > 0 Shif
Page 107 and 108: Normalized Form keeps one digit lef
Page 109 and 110: Let us consider the addition of two
Page 111 and 112: Control path Inputs Exponent differ
Page 113 and 114: Lecture 19 Architectures for Crypto
Page 115 and 116: 1. Following pseudo code represents
Page 117 and 118: Find 7 36 mod 11 using right to lef
Page 119 and 120: Lecture 20 - Performance Chapter -
Page 121 and 122: total amount of work done in a give
Page 123 and 124: Question 4 Assuming the CPI for pro
Page 125 and 126: Question 9 Yet another user has the
Page 127 and 128: Question 12 Assuming the CPI values
Page 129 and 130: Use C2 CPI on M1 = 4*0.3+6*0.2+8*0.
Page 131 and 132: Question 15 We are interested in tw
Page 133 and 134: Question 18 You are the lead design
Page 135 and 136: Arithmetic Logic unit Register file
Page 137 and 138: Lecture 22 - Processor Design - Dat
Page 139 and 140: Example Design the data path to fet
Page 141 and 142: Now combine two functional units to
Page 143 and 144: Lecture 23 Processor Design - Data
Page 145 and 146: Example : - Design DataPath for SW
Page 147 and 148: Processor Design - Data path for R&
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Example : - Implement R+ I +J Forma
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31 26 0 4 control signals EX/Addres
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Draw the logic circuit _ _ _ _ _ _
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Single cycle implementation of the
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from Aluop B from output PC Data Ad
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Lecture 27 High level view of the F
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0 Page | 161 1 2 3 5 4 0 - MemRead
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FSM Controller for lw/sw 6 states 0
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Lecture 28 R-type instruction conti
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Branch Instruction Fetch Page | 167
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Jump Inst Fetch Page | 169 Inst dec
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Page | 171
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0 1 Page | 173 2 6 8 9 3 5 7 4 op 0
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NS0 = 1 + 3 + 5 + 7 + 9 NS1 = 2 + 3
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Lecture 30 Microprogramming - FSM c
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- Microinstruction placed in a ROM
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- In multicycle design - assume tha
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Multi-cycle implementation of the M
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2.5 Draw the functional units neces
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2.9 The instruction, addi (add imme
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Problems with pipelining Hazards Da
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Ex: Represent the 5 stage pipeline
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Example Represent the 5 stage pipel
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Example: Find the size of each pipe
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Pipelined control path - Single cyc
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Control signals with instructions E
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Ex: Show the control signals genera
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Ex: Show the control signals genera
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Lecture 33 Forwarding Unit Design E
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Example: Illustrate the forwarding
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Design a Forwarding unit to integra
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Ex: Forwarding with 2 inst. (1) add
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Lecture 34 Data hazard and stalls F
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Tomasulo • Lasting Contributions
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Tomasulo Organization Page | 217
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4. Show the pipeline execution of f
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7. Illustrate the pipelined data pa
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11. Reorder the following instructi
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15. Design the forwarding unit for
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Temporal locality Low Data Accessin
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Associative mapping More flexible m
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Problems 1. Here is a series of add
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6. What are the miss rate of the fo
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Installation and Usage of Maxplus I
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intend to read registers this instr
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Tomasulo hardware algorithm From Wi
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When all operands are available o I
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Lecture Notes for Computer Architecture II - St. Cloud State University

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