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Chapter 6 – Section 2 (5/2/04) Page 6.2-12<br />
Compensated Open-Loop Frequency Response of the Two-Stage Op Amp<br />
|A(jω)F(jω)|<br />
A vd (0) dB<br />
Compensated<br />
Uncompensated<br />
-20dB/decade<br />
Arg[-A(jω)F(jω)|<br />
Note that the unity-gainbandwidth, GB, is<br />
GB<br />
0dB<br />
log 10 (ω)<br />
Phase Shift<br />
Uncompensated<br />
-40dB/decade<br />
180°<br />
135°<br />
-45°/decade<br />
90°<br />
-45°/decade<br />
Compensated<br />
45°<br />
Phase<br />
No phase margin<br />
Margin<br />
0°<br />
log 10 (ω)<br />
|p 1 | |p 1 '| |p 2 '| |p 2 |<br />
Fig. 120-12<br />
1<br />
GB = A vd (0)·|p 1 | = (g mI g mII R I R II ) g mII R I R II C = g mI<br />
c C = g m1<br />
c C = g m2<br />
c C c<br />
CMOS <strong>Analog</strong> Circuit <strong>Design</strong> © P.E. Allen - 2004<br />
Chapter 6 – Section 2 (5/2/04) Page 6.2-13<br />
Conceptually, where do these roots come from?<br />
1.) The Miller pole:<br />
V DD<br />
|p 1 | ≈<br />
1<br />
R I (g m6 R II C c )<br />
R I<br />
C c<br />
R II<br />
v out<br />
M6<br />
v I<br />
≈g m6 R II C c<br />
Fig. 120-13<br />
2.) The left-half plane output pole:<br />
V DD<br />
|p 2 | ≈ g m6<br />
C II<br />
C c<br />
R II<br />
v out<br />
M6<br />
C II<br />
1<br />
GB·C<br />
≈ 0 c<br />
V DD<br />
R II<br />
v out<br />
M6<br />
C II<br />
3.) Right-half plane zero (One source of zeros is from<br />
multiple paths from the input to output):<br />
g<br />
-g<br />
v out = ⎜ ⎜⎛ m6 R II (1/sC c ) R -R ⎜⎛ m6<br />
II⎝ ⎜<br />
⎝<br />
R<br />
⎠ ⎟⎟⎞<br />
II + 1/sC c<br />
v’ + ⎜ ⎜⎛ II<br />
sC<br />
⎠ ⎟⎟⎞ c<br />
- 1<br />
⎝<br />
R<br />
⎠ ⎟⎟⎞<br />
II + 1/sC c<br />
v’’ = R II + 1/sC c<br />
v<br />
where v = v’ = v’’.<br />
v''<br />
v'<br />
C c<br />
Fig. 120-14<br />
V DD<br />
R II<br />
v out<br />
M6<br />
Fig. 120-15<br />
CMOS <strong>Analog</strong> Circuit <strong>Design</strong> © P.E. Allen - 2004