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chapter 6 - Analog IC Design.org

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Chapter 6 – Section 2 (5/2/04) Page 6.2-12<br />

Compensated Open-Loop Frequency Response of the Two-Stage Op Amp<br />

|A(jω)F(jω)|<br />

A vd (0) dB<br />

Compensated<br />

Uncompensated<br />

-20dB/decade<br />

Arg[-A(jω)F(jω)|<br />

Note that the unity-gainbandwidth, GB, is<br />

GB<br />

0dB<br />

log 10 (ω)<br />

Phase Shift<br />

Uncompensated<br />

-40dB/decade<br />

180°<br />

135°<br />

-45°/decade<br />

90°<br />

-45°/decade<br />

Compensated<br />

45°<br />

Phase<br />

No phase margin<br />

Margin<br />

0°<br />

log 10 (ω)<br />

|p 1 | |p 1 '| |p 2 '| |p 2 |<br />

Fig. 120-12<br />

1<br />

GB = A vd (0)·|p 1 | = (g mI g mII R I R II ) g mII R I R II C = g mI<br />

c C = g m1<br />

c C = g m2<br />

c C c<br />

CMOS <strong>Analog</strong> Circuit <strong>Design</strong> © P.E. Allen - 2004<br />

Chapter 6 – Section 2 (5/2/04) Page 6.2-13<br />

Conceptually, where do these roots come from?<br />

1.) The Miller pole:<br />

V DD<br />

|p 1 | ≈<br />

1<br />

R I (g m6 R II C c )<br />

R I<br />

C c<br />

R II<br />

v out<br />

M6<br />

v I<br />

≈g m6 R II C c<br />

Fig. 120-13<br />

2.) The left-half plane output pole:<br />

V DD<br />

|p 2 | ≈ g m6<br />

C II<br />

C c<br />

R II<br />

v out<br />

M6<br />

C II<br />

1<br />

GB·C<br />

≈ 0 c<br />

V DD<br />

R II<br />

v out<br />

M6<br />

C II<br />

3.) Right-half plane zero (One source of zeros is from<br />

multiple paths from the input to output):<br />

g<br />

-g<br />

v out = ⎜ ⎜⎛ m6 R II (1/sC c ) R -R ⎜⎛ m6<br />

II⎝ ⎜<br />

⎝<br />

R<br />

⎠ ⎟⎟⎞<br />

II + 1/sC c<br />

v’ + ⎜ ⎜⎛ II<br />

sC<br />

⎠ ⎟⎟⎞ c<br />

- 1<br />

⎝<br />

R<br />

⎠ ⎟⎟⎞<br />

II + 1/sC c<br />

v’’ = R II + 1/sC c<br />

v<br />

where v = v’ = v’’.<br />

v''<br />

v'<br />

C c<br />

Fig. 120-14<br />

V DD<br />

R II<br />

v out<br />

M6<br />

Fig. 120-15<br />

CMOS <strong>Analog</strong> Circuit <strong>Design</strong> © P.E. Allen - 2004

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