13.11.2014 Views

chapter 6 - Analog IC Design.org

chapter 6 - Analog IC Design.org

chapter 6 - Analog IC Design.org

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

Chapter 6 – Section 3 (5/2/04) Page 6.3-4<br />

Op Amp Specifications<br />

The following design procedure assumes that specifications for the following parameters<br />

are given.<br />

1. Gain at dc, A v (0)<br />

2. Gain-bandwidth, GB<br />

3. Phase margin (or settling time)<br />

4. Input common-mode range, <strong>IC</strong>MR<br />

5. Load Capacitance, C L<br />

6. Slew-rate, SR<br />

-<br />

7. Output voltage swing<br />

+<br />

8. Power dissipation, P diss<br />

Max. <strong>IC</strong>MR<br />

and/or p 3 V DD<br />

+<br />

V V +<br />

V out (max)<br />

SG4 SG6 -<br />

-<br />

M6 g m6 or<br />

M3 M4<br />

C c I 6<br />

Proper Mirroring<br />

V SG4 =V SG6<br />

GB = g m1<br />

C c<br />

v out<br />

C<br />

v L<br />

in<br />

C M1 M2 c ≈ 0.2C L<br />

(PM = 60°)<br />

Min. <strong>IC</strong>MR I 5 I5 = SR·C c V out (min)<br />

+<br />

VBias<br />

-<br />

M5<br />

V SS<br />

M7<br />

Fig. 160-02<br />

CMOS <strong>Analog</strong> Circuit <strong>Design</strong> © P.E. Allen - 2004<br />

Chapter 6 – Section 3 (5/2/04) Page 6.3-5<br />

Unbuffered Op Amp <strong>Design</strong> Procedure<br />

This design procedure assumes that the gain at dc (A v ), unity gain bandwidth (GB), input<br />

common mode range (V in (min) and V in (max)), load capacitance (C L ), slew rate (SR),<br />

settling time (T s ), output voltage swing (V out (max) and V out (min)), and power dissipation<br />

(P diss ) are given. Choose the smallest device length which will keep the channel<br />

modulation parameter constant and give good matching for current mirrors.<br />

1. From the desired phase margin, choose the minimum value for C c , i.e. for a 60° phase<br />

margin we use the following relationship. This assumes that z ≥ 10GB.<br />

C c > 0.22C L<br />

2. Determine the minimum value for the “tail current” (I 5 ) from the largest of the two<br />

values.<br />

I 5 = SR .C c or I 5 ≅ 10⎜ ⎛ V DD + |V SS |<br />

⎝ 2 . ⎠ ⎟⎞<br />

Ts<br />

3. <strong>Design</strong> for S 3 from the maximum input voltage specification.<br />

I 5<br />

S 3 = K' 3 [V DD − V in (max) − |V T03 |(max) + V T1 (min)]2<br />

4. Verify that the pole of M3 due to C gs3 and C gs4 (= 0.67W 3 L 3 C ox ) will not be dominant by<br />

assuming it to be greater than 10 GB<br />

g m3<br />

2C gs3<br />

> 10GB.<br />

CMOS <strong>Analog</strong> Circuit <strong>Design</strong> © P.E. Allen - 2004

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!