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ottawa county sewer district wastewater rules and regulations for ...

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disconnection shall occur no earlier than thirty (30) days after service of<br />

a written notice of disconnection.<br />

INFILTRATION AND INFLOW<br />

TABLE “A”<br />

Calculation <strong>for</strong> Infiltration/Inflow:<br />

Since Ohio EPA uses 400 gallons per day per equivalent dwelling unit (EDU) as a<br />

design st<strong>and</strong>ard <strong>and</strong> Ottawa County uses the Ohio EPA st<strong>and</strong>ard as a basis <strong>for</strong> current<br />

billing, the SSES Policy was correlated with this st<strong>and</strong>ard while using the U.S. EPA<br />

h<strong>and</strong>book Sewer System Infrastructure Analysis <strong>and</strong> Rehabilitation <strong>and</strong> the American<br />

Society of Civil Engineers’ Existing Sewer Evaluation <strong>and</strong> Rehabilitation, WEF Manual<br />

of Practice FD-6, ASCE Manuals <strong>and</strong> Reports on Engineering Practice No. 62, second<br />

edition, as additional resources.<br />

The Ohio EPA St<strong>and</strong>ard is based on 100 gallons per capita day (gpcd) usage <strong>and</strong> four<br />

(4) people per family or 400 gpd/EDU. The Ohio EPA 100 gpcd st<strong>and</strong>ard could be<br />

further allocated as 80 gpcd <strong>for</strong> domestic flow <strong>and</strong> 20 gpcd as infiltration based on U.S.<br />

EPA criteria.<br />

The ASCE’s Exiting Sewer Evaluation <strong>and</strong> Rehabilitation, Existing Sewer Evaluation<br />

<strong>and</strong> Rehabilitation, WEF Manual of Practice FD-6, ASCE Manuals <strong>and</strong> Reports on<br />

Engineering Practice No. 62, second edition, states, “Even in a well constructed,<br />

separated system, the ratio of wet maximum to dry average usually ranges from 2 to 3<br />

<strong>and</strong> wet peak to dry average from 3 to 4; higher values indicated a more pronounced<br />

problem.<br />

A. Ohio EPA EDU = 400 gpd (based on 100 gpcd)<br />

= 320 gpd (based on 80 gpcd domestic flow)<br />

= Wet Max = 3 x 320 = 960 gpd/EDU<br />

= Wet Peak = 4 x 320 = 1,280 gpd/EDU<br />

Summary<br />

1. The highest wet maximum flow would be 960 gpd per EDU. Under no<br />

circumstances will the acceptable wet maximum flow exceed this amount.<br />

2. The highest wet peak flow would be 1,280 gpd per EDU divided by 1440 minutes =<br />

0.889 gpm. Under no circumstances will the acceptable wet peak flow rate exceed<br />

this amount.

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