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H. Repeat part D for the following functions, using the given intervals.<br />

i.<br />

ii.<br />

iii.<br />

iv.<br />

v.<br />

f 1x2 x 2 6x 3, 4 x 8<br />

f 1x2 4x 2 12x 7, 2 x 6<br />

f 1x2 x 3 3x 2 9x 10, 2 x 6<br />

f 1x2 x 3 12x 5, 0 x 5<br />

f 1x2 x 3 5x 2 3x 7, 2 x 5<br />

I. In parts C and F, you saw that a maximum or minimum can occur at points<br />

1c, f 1c22, where f ¿1c2 0. From your observations in part H, state other values<br />

of the variable that can produce a maximum or minimum in a given interval.<br />

Checkpoint: Check Your Understanding<br />

The maximum value of a function that has a derivative at all points in an interval<br />

occurs at a “peak” 1 f ¿1c2 02 or at an endpoint of the interval. The minimum<br />

value occurs at a “valley” 1 f ¿1c2 02 or at an endpoint. This is true no matter<br />

how many peaks and valleys the graph has in the interval.<br />

In the following three graphs, the derivative equals zero at two points:<br />

maximum<br />

y<br />

maximum<br />

y<br />

y<br />

maximum<br />

0<br />

minimum<br />

x<br />

minimum<br />

x<br />

minimum<br />

x<br />

Algorithm for Finding Maximum or Minimum (Extreme) Values<br />

If a function f 1x2 has a derivative at every point in the interval a x b,<br />

calculate f 1x2 at<br />

• all points in the interval a x b, where f ¿1x2 0<br />

• the endpoints x a and x b<br />

The maximum value of f 1x2 on the interval a x b is the largest of these<br />

values, and the minimum value of f 1x2 on the interval is the smallest of these values.<br />

When using the algorithm above it is important to consider the function f(x) on a<br />

finite interval—that is, an interval that includes its endpoints. Otherwise, the function<br />

may not attain a maximum or minimum value.<br />

NEL CHAPTER 3 131

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