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EXAMPLE 3<br />

Using logarithmic differentiation<br />

dy<br />

Given y 1 x 4 12 x 2<br />

determine at x 1.<br />

dx<br />

12x 2 2x 12 ,<br />

Solution<br />

dy<br />

While it is possible to determine using a combination of the product, quotient,<br />

dx<br />

and chain rules, this process is awkward and time-consuming. Instead, before<br />

differentiating, we take the natural logarithm of both sides of the equation.<br />

Since y 1x4 12 x 2<br />

12x 2 2x 12 ,<br />

ln y ln c 1x4 12x 2<br />

12x 2 d<br />

2x 12<br />

ln y ln 1x 4 12 ln x 2 ln 12x 2 2x 12<br />

ln y ln 1x 4 12 1 2 ln 1x 22 ln 12x2 2x 12<br />

The right side of this equation looks much simpler. We can now differentiate both<br />

sides with respect to x, using implicit differentiation on the left side.<br />

1 dy<br />

y dx 1<br />

x 4 1 14x3 2 1 1<br />

2 x 2 1<br />

2x 2 14x 22<br />

2x 1<br />

dy<br />

dx y c 4x 3<br />

x 4 1 1<br />

21x 22 4x 2<br />

2x 2 2x 1 d<br />

1x4 12 x 2 4x 3<br />

12x 2 c<br />

2x 12 x 4 1 1<br />

21x 22 4x 2<br />

2x 2 2x 1 d<br />

While this derivative is a very complicated function, the process of determining<br />

the derivative is straightforward, using only the derivative of the natural logarithmic<br />

function and the chain rule.<br />

We do not need to simplify this in order to determine the value of the derivative<br />

at x 1.<br />

For x 1, dy 11 12 1<br />

<br />

dx 12 2 12 c 4<br />

1 1 1<br />

211 22 4 2<br />

2 2 1 d<br />

2 c 2 1 2 2 d<br />

1<br />

CALCULUS APPENDIX—LOGARITHMIC DIFFERENTIATION 581<br />

NEL

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